#include<stdio.h>int main(){inta,b; scanf("%2d%*3d%2d",&a,&b);printf("a=%d b=%d

#include<stdio.h>int main(){inta,b; scanf("%2d%*3d%2d",&a,&b);printf("a=%d b=%d\n",a,b);return 0;}

scanf("%2d%*3d%2d",&a,&b);
是scanf("%d%d",&a,&b);

这没有错误，要说有错误，就是inta,b;那里应该为int a,b;
它的意思是读取2位数字的a，忽略掉3位数字，然后再读取2位数字的b。
#include
int main()
{int a,b; scanf("%2d%*3d%2d",&a,&b);
printf("a=%d b=%d ",a,b);
return 0;
}