iOS 给服务器传JSON数据如何处理掉\n
答案:1 悬赏:0 手机版
解决时间 2021-03-22 22:38
- 提问者网友:黑米和小志
- 2021-03-21 23:12
iOS 给服务器传JSON数据如何处理掉\n
最佳答案
- 五星知识达人网友:不甚了了
- 2021-03-22 00:06
代码如下:
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
//申明返回的结果是json类型
manager.responseSerializer = [AFJSONResponseSerializer serializer];
//申明请求的数据是json类型
manager.requestSerializer=[AFJSONRequestSerializer serializer];
//如果报接受类型不一致请替换一致text/html或别的
manager.responseSerializer.acceptableContentTypes = [NSSet setWithObject:@"text/html"];
//传入的参数
NSDictionary *parameters = @{@"1":@"XXXX",@"2":@"XXXX",@"3":@"XXXXX"};
//你的接口地址
NSString *url=@"http://xxxxx";
//发送请求
[manager POST:url parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSLog(@"JSON: %@", responseObject);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
}];
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
//申明返回的结果是json类型
manager.responseSerializer = [AFJSONResponseSerializer serializer];
//申明请求的数据是json类型
manager.requestSerializer=[AFJSONRequestSerializer serializer];
//如果报接受类型不一致请替换一致text/html或别的
manager.responseSerializer.acceptableContentTypes = [NSSet setWithObject:@"text/html"];
//传入的参数
NSDictionary *parameters = @{@"1":@"XXXX",@"2":@"XXXX",@"3":@"XXXXX"};
//你的接口地址
NSString *url=@"http://xxxxx";
//发送请求
[manager POST:url parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSLog(@"JSON: %@", responseObject);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
}];
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