若x+y=-1,则x四次方+5x³y+x²y+8x²y²+xy²+5xy³+y四次方的值等于
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解决时间 2021-04-11 00:12
- 提问者网友:几叶到寒
- 2021-04-10 09:03
若x+y=-1,则x四次方+5x³y+x²y+8x²y²+xy²+5xy³+y四次方的值等于
最佳答案
- 五星知识达人网友:从此江山别
- 2021-04-10 10:06
x⁴+5x³y+x²y+8x²y²+xy²+5xy³+y⁴
=x⁴+4x³y+6x²y²+4xy³+y⁴+x³y+2x²y²+xy³ +x²y+xy²
=(x+y)⁴+xy(x²+2xy+y²)+xy(x+y)
=(x+y)⁴+xy(x+y)²+xy(x+y)
=(-1)⁴+xy(-1)²+xy(-1)
=1+xy-xy
=1
=x⁴+4x³y+6x²y²+4xy³+y⁴+x³y+2x²y²+xy³ +x²y+xy²
=(x+y)⁴+xy(x²+2xy+y²)+xy(x+y)
=(x+y)⁴+xy(x+y)²+xy(x+y)
=(-1)⁴+xy(-1)²+xy(-1)
=1+xy-xy
=1
全部回答
- 1楼网友:拾荒鲤
- 2021-04-10 11:03
x^4+5x^3y+x^2y+8x^2y^2+xy^2+5xy^3+y^4
=(x^4+x^3y)+(4x^3y+4x^2y^2)+(4x^2y^2+4xy^3)+(xy^3+y^4)+(x^2y+xy^2)
=-x^3-4x^2y-4xy^2-y^3-xy
=-(x^3+y^3)-4(x^2y+xy^2)-xy
=(x^2+y^2-xy)+4xy-xy
=(x+y)^2=1
- 2楼网友:行路难
- 2021-04-10 10:40
x^4+5x³y+x²y+8x²y²+xy²+5xy³+y^4
=x^4+4x^3y+6x^2y^2+4xy^3+y^4+x^3y+x^2y+2x^2y^2+xy^2+xy^3
=(x+y)^4+xy(x^2+y^2)+xy(x+y)+2x^2y^2
=1+xy[(x+y)^2-2xy]-xy+2x^2y^2
=1+xy(1-2xy)-xy+2x^2y^2
=1+xy-2x^2y^2-xy+2x^2y^2
=1
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