已知y=√-2cos^2x+3cosx-1+lg(36-x^2)的定义域
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解决时间 2021-01-15 22:04
- 提问者网友：几叶到寒
- 2021-01-15 03:45
已知y=√-2cos^2x+3cosx-1+lg(36-x^2)的定义域
最佳答案
- 五星知识达人网友：一把行者刀
- 2021-01-15 04:04
y=√-2cos^2x+3cosx-1+lg(36-x^2)
-2cos^2x+3cosx-1>=0
(36-x^2)>0
-2cos^2x+3cosx-1>=0
2cos^2x-3cosx+1<=0
(2cosx-1)(cosx-1)<=0
1/2<=cosx<=1
2kπ-π/3<=x<=2kπ+π/3
(36-x^2)>0
x^2<36
-6
-2cos^2x+3cosx-1>=0
(36-x^2)>0
-2cos^2x+3cosx-1>=0
2cos^2x-3cosx+1<=0
(2cosx-1)(cosx-1)<=0
1/2<=cosx<=1
2kπ-π/3<=x<=2kπ+π/3
(36-x^2)>0
x^2<36
-6
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