汇编程序设计
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解决时间 2021-04-13 15:20
- 提问者网友:抽煙菂渘情少年
- 2021-04-12 16:29
编程实现:输入字符串(最大串长自定),使用冒泡排序法进行排序,在屏幕上显示排序后的字符串
最佳答案
- 五星知识达人网友:神的生死簿
- 2021-04-12 17:59
assume cs:code, ds:datas
datas segment
str db 100 dup(?)
datas ends
code segment
start:
mov ax, datas
mov ds, ax
lea bx, str
xor cx, cx
mov ah, 1
next:
int 21h
cmp al, 13
jz ok
mov [bx], al
inc bx
inc cx
jmp next
ok:
mov al, '$'
mov [bx], al
mov ah, 2
mov dl, 13
int 21h
mov dl, 10
int 21h
mov di, cx
xor cx, cx
jmp cp1
upd1:
inc cx
cp1:
cmp cx, di
jz done
mov si, di
upd2:
dec si
cp2:
cmp si, cx
jle ok1
mov al, [si]
cmp al, [si-1]
jge noop
xchg al, [si-1]
mov [si], al
noop:
jmp upd2
ok1:
jmp upd1
done:
lea dx, str
mov ah, 9
int 21h
mov ax, 4c00h
int 21h
code ends
end start
datas segment
str db 100 dup(?)
datas ends
code segment
start:
mov ax, datas
mov ds, ax
lea bx, str
xor cx, cx
mov ah, 1
next:
int 21h
cmp al, 13
jz ok
mov [bx], al
inc bx
inc cx
jmp next
ok:
mov al, '$'
mov [bx], al
mov ah, 2
mov dl, 13
int 21h
mov dl, 10
int 21h
mov di, cx
xor cx, cx
jmp cp1
upd1:
inc cx
cp1:
cmp cx, di
jz done
mov si, di
upd2:
dec si
cp2:
cmp si, cx
jle ok1
mov al, [si]
cmp al, [si-1]
jge noop
xchg al, [si-1]
mov [si], al
noop:
jmp upd2
ok1:
jmp upd1
done:
lea dx, str
mov ah, 9
int 21h
mov ax, 4c00h
int 21h
code ends
end start
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