分解因式:3m乘上(2x-y)的平方-3乘mn的平方
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解决时间 2021-03-03 22:29
- 提问者网友:了了无期
- 2021-03-02 21:37
分解因式:3m乘上(2x-y)的平方-3乘mn的平方
最佳答案
- 五星知识达人网友:酒者煙囻
- 2021-03-02 21:47
(1)x的平方-6x-7
=(x-7)(x+1)(2)3乘以x的平方-6x+1
=3[x-(3+√6)/3][x-(3-√6)/3](3)x的平方乘以(y-x)+y的平方乘以(x-y)
=x??(y-x)-y??(y-x)
=(y-x)(x??-y??)
=(y-x)(x+y)(x-y)
=-(y-x)??(x+y)(4)(4乘以x的平方+y的平方)的平方-16乘以x的平方乘以y的平方
=(4x??+y??)??-(4xy)??
=(4x??+y??+4xy)(4x??+y??-4xy)
=(2x+y)??(2x-y)??(5)m的平方-2m+1-n的平方
=(m-1)??-n??
=(m-1+n)(m-1-n)(6)(x-2y)的平方-a的平方+6ab-9乘以b的平方
=(x-2y)??-(a??-6ab+9b??)
=(x-2y)??-(a-3b)??
=(x-2y+a-3b)(x-2y-a+3b)(7)x的(n+1)次方-8乘以x的n次方+16乘以x的(n-1)次方
=x^(n+1)-8x^n+16x^(n-1)
=x^(n-1)·(x??-8x+16)
=x^(n-1)·(x-4)??(8)(x+y)的平方-4(x+y-1)
=(X+y)??-4(x+y)+4
=(x+y-2)??(9)4乘以x的平方y的平方-(x的平方+y的平方)的平方
=(2xy)??-(x??+y??)??
=(2xy+x??+y??)(2xy-x??-y??)
=(x+y)??[-(x??-2xy+y??)]
=-(x+y)??(x-y)??(10)(x+y)的(m+1)次方-(x+y)的(m-1)次方(m为大于1的正整数)
=(x+y)^(m-1)·[(x+y)??-1]
=(x+y)^(m-1)·(x+y+1)(x+y-1)已知多项式2乘以x的平方+3xy-2乘以y的平方+8y-x-6=(x+2y+m)(2x-y+n),求m的平方+n的平方的值
∵(x+2y+m)(2x-y+n)
=2x??-xy+nx+4xy-2y??-2ny+2mx-my+mn
=2x??+3xy-2y??+(2n-m)y+(n+2m)x+mn
=2x??+3xy-2y??+8y-x-6
∴2n-m=8……①
n+2m=-1……②
mn=-6
①×2+②,得5n=15,n=3
把n=3代入①,得6-m=8
∴m=-2
∴m=-2n=3
m??+n??=(-2)??+3??=13
=(x-7)(x+1)(2)3乘以x的平方-6x+1
=3[x-(3+√6)/3][x-(3-√6)/3](3)x的平方乘以(y-x)+y的平方乘以(x-y)
=x??(y-x)-y??(y-x)
=(y-x)(x??-y??)
=(y-x)(x+y)(x-y)
=-(y-x)??(x+y)(4)(4乘以x的平方+y的平方)的平方-16乘以x的平方乘以y的平方
=(4x??+y??)??-(4xy)??
=(4x??+y??+4xy)(4x??+y??-4xy)
=(2x+y)??(2x-y)??(5)m的平方-2m+1-n的平方
=(m-1)??-n??
=(m-1+n)(m-1-n)(6)(x-2y)的平方-a的平方+6ab-9乘以b的平方
=(x-2y)??-(a??-6ab+9b??)
=(x-2y)??-(a-3b)??
=(x-2y+a-3b)(x-2y-a+3b)(7)x的(n+1)次方-8乘以x的n次方+16乘以x的(n-1)次方
=x^(n+1)-8x^n+16x^(n-1)
=x^(n-1)·(x??-8x+16)
=x^(n-1)·(x-4)??(8)(x+y)的平方-4(x+y-1)
=(X+y)??-4(x+y)+4
=(x+y-2)??(9)4乘以x的平方y的平方-(x的平方+y的平方)的平方
=(2xy)??-(x??+y??)??
=(2xy+x??+y??)(2xy-x??-y??)
=(x+y)??[-(x??-2xy+y??)]
=-(x+y)??(x-y)??(10)(x+y)的(m+1)次方-(x+y)的(m-1)次方(m为大于1的正整数)
=(x+y)^(m-1)·[(x+y)??-1]
=(x+y)^(m-1)·(x+y+1)(x+y-1)已知多项式2乘以x的平方+3xy-2乘以y的平方+8y-x-6=(x+2y+m)(2x-y+n),求m的平方+n的平方的值
∵(x+2y+m)(2x-y+n)
=2x??-xy+nx+4xy-2y??-2ny+2mx-my+mn
=2x??+3xy-2y??+(2n-m)y+(n+2m)x+mn
=2x??+3xy-2y??+8y-x-6
∴2n-m=8……①
n+2m=-1……②
mn=-6
①×2+②,得5n=15,n=3
把n=3代入①,得6-m=8
∴m=-2
∴m=-2n=3
m??+n??=(-2)??+3??=13
全部回答
- 1楼网友:鸠书
- 2021-03-03 00:44
3m(2x-y+n)(2x-y-n)
- 2楼网友:渊鱼
- 2021-03-02 23:23
3m(2x-y)??-3mn??=3m[(2x-y)??-n??]=3m(2x-y+n)(2x-y-n)
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