填空(x-y)(x2+xy+y2)=______;(x-y)(x3+x2y+xy2+y3)=______根据以上等式进行猜想,当n是偶数时,
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解决时间 2021-01-28 21:16
- 提问者网友:我的未来我做主
- 2021-01-27 23:09
填空(x-y)(x2+xy+y2)=______;(x-y)(x3+x2y+xy2+y3)=______根据以上等式进行猜想,当n是偶数时,
最佳答案
- 五星知识达人网友:思契十里
- 2021-01-28 00:35
原式=x3+x2y+xy2-x2y-xy2-y3=x3-y3;
故答案为:x3-y3;
原式=x4+x3y+x2y2+xy3-x3y-x2y2-xy3-y4=x4-y4;
故答案为:x4-y4;
原式=xn+1+xny+xyn-2+x2yn-1+xyn-xny-xn-1y2-yn-1y2-…-x2yn-1-xyn-yn+1=xn+1-yn+1,
故答案为:xn+1-yn+1.
故答案为:x3-y3;
原式=x4+x3y+x2y2+xy3-x3y-x2y2-xy3-y4=x4-y4;
故答案为:x4-y4;
原式=xn+1+xny+xyn-2+x2yn-1+xyn-xny-xn-1y2-yn-1y2-…-x2yn-1-xyn-yn+1=xn+1-yn+1,
故答案为:xn+1-yn+1.
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