用C语言解决"1-1/2!+1/3!+1/4!+1/5!+1/6!...直到最后一项的值小于1/1000000为止"

用C语言解决"1-1/2!+1/3!+1/4!+1/5!+1/6!...直到最后一项的值小于1/1000000为止"

#include<stdio.h>
main()
{
double sum=0,term=1,i;
do
{
for(i=2;i<=10;i++)
{

term=term*1/i;
sum=sum+term;
}
}while(term<(1/1000000));
sum=1-sum;
printf("%lf",sum);
}

我是菜鸟，写的比较简单

main() { int a,b,c,i; double y=0; y=1-1/2; for(i=3;i<10000;i++) { y+=1/i; } printf("%f",y); }

//先做个阶乘的函数

factorial(int n) {

if(n == 0)

return 1;

else

return n*factorial(n - 1);

}

//计算函数

int compute(int n) {

longint result;

for(n=2;n<=1000000) {

result = result + 1/factorial(n);

}

result = 1 - result;

return result;

}

double sum = 0;

int k = 1;

int i ;

for ( i = 2 ; ; i ++ )

{

k *=i;

sum + = 1.0 / k;

if(1.0 / k) break;

}

return sum;

方法体大概就是这样