因式分解,请附上步骤 (c+d)2次-9(2d-c)2次 12-3(e+2f)2次 98(g-h)2次-50g2次 75k-3k(2k-1)2次
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解决时间 2021-11-26 08:52
- 提问者网友：寂寞撕碎了回忆
- 2021-11-26 02:59
因式分解,请附上步骤 (c+d)2次-9(2d-c)2次 12-3(e+2f)2次 98(g-h)2次-50g2次 75k-3k(2k-1)2次
最佳答案
- 五星知识达人网友：鱼忧
- 2021-11-26 04:24
解：
(c+d)²-9(2d-c)²
=(c+d)²-[3(2d-c)]²
=[(c+d)+3(2d-c)][(c+d)-3(2d-c)]
=(7d-2c)(4c-5d)
12-3(e+2f)²
=3[4-(e+2f)²]
=3[2+(e+2f)][2-(e+2f)]
=2(e+2f+2)(2-e-2f)
98(g-h)²-50g²
=2[49(g-h)²-25g²]
=2[7(g-h)+5g][7(g-h)-5g]
=2(12g-7h)(2g-7h)
75k-3k(2k-1)²
=-3k[(2k-1)²-25]
=-3k[(2k-1)+5][(2k-1)-5]
=-3k(2k+4)(2k-6)
=-12k(k+2)(k-3)
(c+d)²-9(2d-c)²
=(c+d)²-[3(2d-c)]²
=[(c+d)+3(2d-c)][(c+d)-3(2d-c)]
=(7d-2c)(4c-5d)
12-3(e+2f)²
=3[4-(e+2f)²]
=3[2+(e+2f)][2-(e+2f)]
=2(e+2f+2)(2-e-2f)
98(g-h)²-50g²
=2[49(g-h)²-25g²]
=2[7(g-h)+5g][7(g-h)-5g]
=2(12g-7h)(2g-7h)
75k-3k(2k-1)²
=-3k[(2k-1)²-25]
=-3k[(2k-1)+5][(2k-1)-5]
=-3k(2k+4)(2k-6)
=-12k(k+2)(k-3)
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