编写程序判断两个数组是否相等
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解决时间 2021-03-04 22:32
- 提问者网友:雨不眠的下
- 2021-03-04 11:20
编写程序判断两个数组是否相等
最佳答案
- 五星知识达人网友:动情书生
- 2021-03-04 12:03
#include <iostream>
#include <vector>
using namespace std;
int main()
{
vector<int> ivec1, ivec2;
int ival;
//读入两个vector 的元素值
cout << "Enter numbers for vector1(-1 to end):" << endl;
cin >> ival;
while (ival != -1) {
ivec1.push_back(ival);
cin >> ival;
}
cout << "Enter numbers for vector2(-1 to end):" << endl;
cin >> ival;
while (ival != -1) {
ivec2.push_back(ival);
cin >> ival;
}
//判断两个vector 是否相等
if (ivec1.size() != ivec2.size()) //长度不等的vector 不相等
cout << "Vector1 is not equal to vector2." << endl;
else if (ivec1.size() == 0) //长度都为0 的vector 相等
cout << "Vector1 is equal to vector2." << endl;
else {//两个vector 长度相等且不为0
vector<int>::iterator iter1, iter2;
iter1 = ivec1.begin();
iter2 = ivec2.begin();
while (iter1 != ivec1.end() && *iter1 == *iter2) { // 先判断是不是end(),不是才判断是否相等
++iter1;
++iter2;
}
if (iter1 == ivec1.end())//所有元素都相等
cout << "Vector1 is equal to vector2." << endl;
else
cout << "Vector1 is not equal to vector2." << endl;
}
system("pause");
return 0;
}
#include <vector>
using namespace std;
int main()
{
vector<int> ivec1, ivec2;
int ival;
//读入两个vector 的元素值
cout << "Enter numbers for vector1(-1 to end):" << endl;
cin >> ival;
while (ival != -1) {
ivec1.push_back(ival);
cin >> ival;
}
cout << "Enter numbers for vector2(-1 to end):" << endl;
cin >> ival;
while (ival != -1) {
ivec2.push_back(ival);
cin >> ival;
}
//判断两个vector 是否相等
if (ivec1.size() != ivec2.size()) //长度不等的vector 不相等
cout << "Vector1 is not equal to vector2." << endl;
else if (ivec1.size() == 0) //长度都为0 的vector 相等
cout << "Vector1 is equal to vector2." << endl;
else {//两个vector 长度相等且不为0
vector<int>::iterator iter1, iter2;
iter1 = ivec1.begin();
iter2 = ivec2.begin();
while (iter1 != ivec1.end() && *iter1 == *iter2) { // 先判断是不是end(),不是才判断是否相等
++iter1;
++iter2;
}
if (iter1 == ivec1.end())//所有元素都相等
cout << "Vector1 is equal to vector2." << endl;
else
cout << "Vector1 is not equal to vector2." << endl;
}
system("pause");
return 0;
}
全部回答
- 1楼网友:刀戟声无边
- 2021-03-04 14:18
设两个数组a[i],b[j]
if(i==j)
{
for(int r=0;r<i;r++)
{if(a[r]==b[r])
{//两个数组的个元素相等即为两个数组相等}
}
}
- 2楼网友:怀裏藏嬌
- 2021-03-04 13:22
两个方法,第一个比较常规,第二个特别适合字符数组的判断。方法一:char[] a = {'a', 'b'}; char[] b = {'a', 'f'}; //对a, b 数组赋值操作 if (a.length != b.length) { system.out.print("两个数组不相等"); return; } else { for (int i = 0; i < a.length; i++) { if (a[i] != b[i]) { system.out.print("两个数组不相等"); return; } } system.out.println("两个数组不相等"); }方法二: char[] a = {'a', 'b'}; char[] b = {'a', 'f'}; //对a, b 数组赋值操作 string sa = string.valueof(a); string sb = string.valueof(b); if( sa.equals(sb) ) system.out.println("两个数组相等"); else system.out.println("两个数组不相等");
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