编写程序，输入正整数n，计算它的阶乘n！（n！=nx（n-1）x…x3x2x1）

#include <stdio.h>

int main()
{
int i,n;
long sum = 1;
printf("input a number:");
scanf("%d",&n);
if( n == 0)
printf("%d != 1",n);
else
for(i = 1;i <= n;i ++)
sum *= i;
printf("%d! = %ld \n",n,sum);
}

i=1

s=1

while i<=n

s=s*i

i=i+1

wend

print s

end

public static int Num(int n) { int tempNum=n; int temp=n; for(int i=n-1;i>1;i--) { temp*=i; } return temp; }

*********您好!Yadie.23很高兴能为你解答。********* +++++++++++++++++++++++++++++++++++++++++++++++++

代码很简单，我更愿意帮你检查你的代码，给些意见。。

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能问下用哪种语言吗？