(1)已知多项式中3x³-(n+2)x²+4x+5不含二次项,求n的值
(2)已知多项式3a²b³-8ab+5与4a²b+ab-n+2的常数项相同,求n的值
1
3x³-(n+2)x²+4x+5
n+2=0 n=-2
2
3a²b³-8ab+5与4a²b+ab-n+2
5=-n+2 n=-3