(x-8)(x+8)-x(x-1)(x+1),其中x=负二分之一
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解决时间 2021-11-19 05:49
- 提问者网友：树红树绿
- 2021-11-18 18:45
(x-8)(x+8)-x(x-1)(x+1),其中x=负二分之一
最佳答案
- 五星知识达人网友：天凉才是好个秋
- 2021-11-18 18:59
(x-8)(x+8)-x(x-1)(x+1)
=(x²-64)-x(x²-1)
=x²-64-x³+x
=-x³+x²+x-64
=-(-1/2)³+(-1/2)²+(-1/2)-64
=1/8+1/4-1/2-64
=1/8+2/8-4/8-64
=-(1/8+64)
=-64又8分之1
=(x²-64)-x(x²-1)
=x²-64-x³+x
=-x³+x²+x-64
=-(-1/2)³+(-1/2)²+(-1/2)-64
=1/8+1/4-1/2-64
=1/8+2/8-4/8-64
=-(1/8+64)
=-64又8分之1
全部回答
- 1楼网友：从此江山别
- 2021-11-18 22:06
＝-15.75
…
…
- 2楼网友：封刀令
- 2021-11-18 20:41
∵x=-1/2
(x-8)(x+8)-x(x-1)(x+1)=x²-64-x(x²-1)=(-1/2)²-64-(-1/2)×[(-1/2)²-1]=1/4-64+1/2(1/4-1)
=1/4-64+1/2×(-3/4)=1/4-64-3/8=-64又1/8
(x-8)(x+8)-x(x-1)(x+1)=x²-64-x(x²-1)=(-1/2)²-64-(-1/2)×[(-1/2)²-1]=1/4-64+1/2(1/4-1)
=1/4-64+1/2×(-3/4)=1/4-64-3/8=-64又1/8
- 3楼网友：独行浪子会拥风
- 2021-11-18 19:58
=x²-64-x(x²-1）
=-x³+x²+x-64
当x=-1/2时
原式=1/8+1/4-1/2-64
=-64又1/8
=-x³+x²+x-64
当x=-1/2时
原式=1/8+1/4-1/2-64
=-64又1/8
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