(1-x2)(1-y2)+4xy=?
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解决时间 2021-04-25 10:35
- 提问者网友:动次大次蹦擦擦
- 2021-04-24 14:08
(1-x2)(1-y2)+4xy=?
最佳答案
- 五星知识达人网友:独行浪子会拥风
- 2021-04-24 14:27
楼上的两次都没有做完呀,应该是:(1-x2)(1-y2)+4xy=1-2xy+x^2y^2-x^2-y^2+2xy =(xy-1)^2-(x-y)^2 =(xy-1+x-y)(xy-1-x+y) =[(xy+x)-(y+1)][(xy-x)+(y-1)] =[x(y+1)-(y+1)][x(y-1)+(y-1)] =(y+1)(x-1)(x+1)(y-1)仅供参考,谢谢采纳
全部回答
- 1楼网友:想偏头吻你
- 2021-04-24 16:38
1-y^2-x^2+x^2y^2+4xy=(xy+1)^2-(x+y)^2=(xy+1+x+y)(xx+1-x-y)
- 2楼网友:往事埋风中
- 2021-04-24 15:57
(1-x2)(1-y2)+4xy=1-x^2-y^2+x^2y^2+4xy=1-2xy+x^2y^2-x^2-y^2+2xy=(xy-1)^2-(x-y)^2=(xy-1+x-y)(xy-1-x+y)
- 3楼网友:忘川信使
- 2021-04-24 15:04
(1-x2)(1-y2)+4xy=1-2xy+x^2y^2-x^2-y^2+2xy=(xy-1)^2-(x-y)^2=(xy-1+x-y)(xy-1-x+y)
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