(x-y)(x+y-1)+x-y因式分解
答案:3 悬赏:70 手机版
解决时间 2021-11-17 14:13
- 提问者网友：富士山上尢
- 2021-11-16 22:51
(x-y)(x+y-1)+x-y因式分解
最佳答案
- 五星知识达人网友：行雁书
- 2021-11-17 00:26
(x-y)(x+y-1)+x-y
=(x-y)(x+y-1)+(x-y)
=(x-y)(x+y-1+1)
=(x-y)(x+y)
=(x-y)(x+y-1)+(x-y)
=(x-y)(x+y-1+1)
=(x-y)(x+y)
全部回答
- 1楼网友：躲不过心动
- 2021-11-17 02:39
=X²-Y²
- 2楼网友：时间的尘埃
- 2021-11-17 01:06
(x-y)(x+y-1)+x-y
=(x-y)[(x+y-1)+1]
=(x-y)(x+y)
=(x-y)[(x+y-1)+1]
=(x-y)(x+y)
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