C语言问题2： 为小学生设计一个测验简单四则运算的系统

，功能为：完成10道题的解答，每道题10分，测完10道题后，给出总成绩。
说明：
（1）这个题目我要求得很笼统，目的是想看看谁在设计系统的时候考虑得更周全；
（2）据库函数中有一个函数rand可以生成伪随机数，结合srand函数后可以生成真随机数，通过下列说明（含程序或程序段）验证这两个函数的使用并尽可能灵活地应用到本系统的设计中。

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define YES 1
#define NO 0
#define NUM_PROBLEM 10 //题目的数量
#define LIMIT_ADDSUB 100 //加法和减法操作数的上限
#define LIMIT_MULDIV 20 //乘法和除法操作数的上限

int expressionCount = 0;
struct expression
{
int num1;
int num2;
char op;
}expr[NUM_PROBLEM];

int createProblem(void);
int createAddProblem(void);
int createSubProblem(void);
int createMulProblem(void);
int createDivProblem(void);
int expressionExist(int num1, int num2, char op);

int main()
{
int i, answer, result;
float score;

srand((unsigned)time(NULL));
score = 0.0;
for (i = 1; i <= NUM_PROBLEM; ++i)
{
printf("第%2d题: ", i);
result = createProblem();
scanf("%d", &answer);
getchar();
if (result == answer)
score += 100.0/NUM_PROBLEM;
}
printf("Final Score:%.0f\n", score);

return 0;}
int createProblem(void)
{
char op;
int result;

op = rand()%4+1;
switch (op)
{
case 1: //加法
result = createAddProblem();
break;
case 2: //减法
result = createSubProblem();
break;
case 3: //乘法
result = createMulProblem();
break;
case 4: //除法
result = createDivProblem();
break;
default:
exit(1);
}

return result;}
int createAddProblem(void)
{
int num1, num2;

do
{
num1 = rand()%LIMIT_ADDSUB+1;
num2 = rand()%LIMIT_ADDSUB+1;
} while (expressionExist(num1, num2, '+'));
printf("%3d + %3d = ", num1, num2);

return (num1+num2);}
int createSubProblem(void)
{
int num1, num2, temp;

do
{
num1 = rand()%LIMIT_ADDSUB+1;
num2 = rand()%LIMIT_ADDSUB+1;
if (num1 < num2)
{
temp = num1;
num1 = num2;
num2 = temp;
}
} while (expressionExist(num1, num2, '-'));
printf("%3d - %3d = ", num1, num2);

return (num1-num2);}
int createMulProblem(void)
{
int num1, num2;

do
{
num1 = rand()%LIMIT_MULDIV+1;
num2 = rand()%LIMIT_MULDIV+1;
} while (expressionExist(num1, num2, '*'));
printf("%3d * %3d = ", num1, num2);

return (num1*num2);}
int createDivProblem(void)
{
int num1, num2;

do
{
num1 = rand()%LIMIT_MULDIV+1;
num2 = rand()%LIMIT_MULDIV+1;
} while (expressionExist(num1, num2, '/'));
printf("%3d / %3d = ", num1*num2, num1);

return num2;}
int expressionExist(int num1, int num2, char op)
{
int i;

for (i = 0; i < expressionCount; ++i)
{
if (expr[i].num1 == num1 && expr[i].num2 == num2 && expr[i].op == op)
return YES;
}

expr[i].num1 = num1;
expr[i].num2 = num2;
expr[i].op = op;
++expressionCount;

return NO;}
先拿去调试，把问题和需要补充的功能发给我，明天再帮你完善。

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