哪位兄弟帮忙看看这个程序?

我想实现的功能要说也不难 : 从终端接收输入的字符, 每输入一个字符后, 为其动态分配一个字节的空间来保存, 以此类推...若输入的字符为 'e' , 则程序结束. 这个功能用一个函数来实现, 在主函数(main)中调用...具体的代码看下面...本来是写了注释的, 要到这里来发, 就把删掉了....以免越弄越混...

写的可能有点乱........呵呵.

#include <stdio.h>
#include <string.h>
#include <malloc.h>

void Malloc(char **p);

int main(int argc, char **argv)
{
char *p = NULL;
size_t size = 0;
int length = 0;

Malloc(&p);

length = strlen(p);
size = _msize(p);

printf("string : %s\n", p);
printf("length : %d\n", length);
printf("size : %d\n", size);

return 0;

}

void Malloc(char **p)
{
char ch;
char *temp = NULL;
int pos = 0;

if (*p != NULL)
{
return;
}

while (scanf("%c", &ch) && (ch != 'e'))
{

#if 0
*p = realloc(*p, (sizeof (char)) * (pos+1));

if (*p == NULL)
{
break;
}
*(*p + pos) = ch;
pos++;
#endif

#if 1
*p = realloc(*p, (sizeof (char)) * (pos+1));
if (*p == NULL)
{
break;
}
temp = *p;

*(temp + pos) = ch;
pos++;
#endif

}
}

*p = realloc(*p, (sizeof (char)) * (pos+1));
这句改成
*p = (char*)realloc(*p, (sizeof (char)) * (pos+1));

加个转换就编译通过了，运行了下似乎没问题，是不是这个问题？

#include <stdio.h> #include <string.h> #include <malloc.h>

void Malloc(char **p);

int main(int argc, char **argv) { char *p = NULL; size_t size = 0; int length = 0; Malloc(&p); length = strlen(p); size = _msize(p); printf("string : %s\n", p); printf("length : %d\n", length); printf("size : %d\n", size); return 0; }

void Malloc(char **p) { char ch; char *temp = NULL; int pos = 0; if (*p != NULL) { return; } while (scanf("%c", &ch) && (ch != 'e')) { #if 0 *p = realloc(*p, (sizeof (char)) * (pos+1)); if (*p == NULL) { break; } *(*p + pos) = ch; pos++; #endif #if 1 *p =(char *) realloc(*p, (sizeof (char)) * (pos+1)); if (*p == NULL) { break; } temp = *p; *(temp + pos) = ch; pos++; #endif } }

*p = realloc(*p, (sizeof (char)) * (pos+1)); 这句改成*p = (char*)realloc(*p, (sizeof (char)) * (pos+1));