关于c语言实现的任意进制转换谁能给我解答一下？代码如下

答案:1 悬赏:70 手机版

解决时间 2021-10-04 13:09

提问者网友：感性作祟
2021-10-04 00:01

#include
int a[210],len;
void cal(int p, int q) {
bool change = false;
int i, left;
for (i = left = 0; i left = (a[i] + left * p);
a[i] = left / q;
left%=q;
}
if (change) cal(p, q);
printf("%c",left+(left>=10?55:'0'));
}
int main() {
int p = 0, q = 0, t,i;
char s[1100];
for (scanf("%d", &t); t--; printf("\n")) {
scanf("%s", s);
for (p = i = 0; s[i] != ','; p = p*10 + s[i++]-'0');
for (i++, len = 0; s[i] != ','; i++, len++) a[len] = s[i]-(s[i]>='A'?55:'0');
for (q = 0, i++; s[i] != '\0'; i++) q = q * 10 + s[i] - '0';
cal(p, q);
}
}

最佳答案

五星知识达人网友：逃夭
2020-09-14 21:12

#include
int a[210],len;
void cal(int p, int q)
{
    bool change = false;
    int i, left;
    for (i = left = 0; i     {
        left = (a[i] + left * p);
        a[i] = left / q;
        left%=q;
    }
    // 如何商不为0
    if (change)cal(p, q);
    // 输出余数
    printf("%c",left+(left>=10?55:'0'));
}
int main()
{
    int p = 0, q = 0, t,i;
    char s[1100];
    //先输入t，表示循环次数
    for (scanf("%d", &t); t--; printf("\n"))
    {
        scanf("%s", s);
        //输入格式为 p,a,q
        for (p = i = 0; s[i] != ','; p = p*10 + s[i++]-'0');
        //a数组是以十进制保存
        for (i++, len = 0; s[i] != ','; i++, len++) a[len] = s[i]-(s[i]>='A'?55:'0');
        for (q = 0, i++; s[i] != '\0'; i++) q = q * 10 + s[i] - '0';
        cal(p, q);
    }
}

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