怎样用链式结构实现线性表的逆置？请给出源程序来！

请问各位高手，怎样用链式结构实现线性表的逆置?要求用Ｃ＋＋编写。

#include <iostream>
using namespace std;

struct list {
int data;
list* next;
};

int main()
{
int a[] = { 0,1,2,3,4,5,6,7,8,9 };
int i;
list l[10], *prev, *next, *t;
prev = 0;

for ( i = 0; i < 10; ++i ) { // 从数组构造链表
l[i].data = a[i];
l[i].next = 0;
if ( prev )
prev->next = &l[i];
prev = &l[i];
}

prev = 0; next = l;
while ( next ) { // 逆序
t = next->next;
next->next = prev;
prev = next;
next = t;
}
while( prev ) { // 输出
cout << prev->data << ' ';
prev = prev->next;
}
cout.put( '\n' );
}