因式分解求解决。

1.x^2-7xy+12y^2

2.(a-b)^2+11(a-b)+28

3.(x+y)^2-(x+y)-30

4.y^6-7y^3-8

5.x^4-7x^2-18

6.(x^2+x)^2+3(x^2+x)-10

7.(x^2+2x-3)^2+7(x^2+2x-3)-8

8.a^2b-a^2b^5

9.(a+b)^2-5(a+b)-6

10.x^4-5x^2+4

11.x^2+10xy-70y-49.

麻烦请写出过程,

1.x^2-7xy+12y^2

=x^2-3xy-4xy+12y^2

=x(x-3y)+4y(x-3y)

=(x-4y)(x-3y)

2.(a-b)^2+11(a-b)+28

=（a-b+7)(a-b+4)

3.(x+y)^2-(x+y)-30

=(x+y-6)(x+y+5)

4.y^6-7y^3-8

=(y^3-8)(y^3+1)

=(y-2)(y^2-2y+4)(y+1)(y^2-y+1)

5.x^4-7x^2-18

=(x^2+2)(x^2-9)

=(x^2+2)(x+3)(x-3)

6.(x^2+x)^2+3(x^2+x)-10

=(x^2+x+5)(x^2+x-2)

=(x^2+x+5)(x+2)(x-1)

7.(x^2+2x-3)^2+7(x^2+2x-3)-8

=(x^2+2x-3+8)(x^2+2x-3-1)

=(x^2+2x+5)(x^2+2x-4)

8.a^2b-a^2b^5

=a^2b(1-b^4)

=a^2b(1+b^2)(1+b)(1-b)

9.(a+b)^2-5(a+b)-6

=(a+b-2)(a+b-3)

10.x^4-5x^2+4

=(x^2-1)(x^2-4)

=(x+1)(x-1)(x+2)(x-2)

11.题好像错了的

1.x^2-7xy+12y^2=x^2-3xy-4xy+12y^2=x(x-3y)+4y(x-3y)=(x-4y)(x-3y)，或直接用十字相乘。下面各题相同原理。

2.(a-b)^2+11(a-b)+28=（a-b+7)(a-b+4)

3.(x+y)^2-(x+y)-30=(x+y-6)(x+y+5)

4.y^6-7y^3-8=(y^3-8)(y^3+1)=(y-2)(y^2-2y+4)(y+1)(y^2-y+1)

5.x^4-7x^2-18=(x^2+2)(x^2-9)=(x^2+2)(x+3)(x-3)

6.(x^2+x)^2+3(x^2+x)-10=(x^2+x+5)(x^2+x-2)=(x^2+x+5)(x+2)(x-1)

7.(x^2+2x-3)^2+7(x^2+2x-3)-8=(x^2+2x-3+8)(x^2+2x-3-1)=(x^2+2x+5)(x^2+2x-4)

8.a^2b-a^2b^5=a^2b(1-b^4)=a^2b(1+b^2)(1+b)(1-b)

9.(a+b)^2-5(a+b)-6=(a+b-2)(a+b-3)

10.x^4-5x^2+4=(x^2-1)(x^2-4)=(x+1)(x-1)(x+2)(x-2)

11.x^2+10xy-70y-49.=题错了吧？无法分解。