用C++的函数写一段代码：输入一串字符，先输出顺向字符，然后输出逆向字符。

需要用到 fill_array做补充数组吗，然后还要有show_array做顺向输出，最后是Reverse_array做逆向输出。。。。整个代码要有这3个函数在里面。。。。

//双向链表实现
#include<stdio.h>
#include<stdlib.h>
typedef struct node
{
char data;
struct node *next,*prior;
} list;

list *linklist()
{
list *head,*s;
char x;
head=(list*)malloc(sizeof(list));
head->next=head;
head->prior=head;
scanf("%c",&x);
while(x!='\n')
{
s=(list*)malloc(sizeof(list));
s->data=x;
s->prior=head;
s->next=head->next;
head->next->prior=s;
head->next=s;
scanf("%c",&x);
}
return head;
}

int print1(list *h)
{
list *p;
p=h->next;
while(p!=h)
{
printf("%3c",p->data);
p=p->next;
}
printf("\n");
}

int print2(list *h)
{
list *p;
p=h->prior;
while(p!=h)
{
printf("%3c",p->data);
p=p->prior;
}
printf("\n");
}

int main()
{
list *p,*h;
int i;
char x;
h=linklist();
printf("顺序输出\n");
print1(h);
printf("逆序输出\n");
print2(h);
system("pause");
}

#include <iostream> #include <cstring> using namespace std; int main() {     char str[100] = {0};     cout << "input a string:";     gets(str);     cout << str << endl;     for(int i = 1; i <= strlen(str); i++)         cout << str[strlen(str)-i];     cout << endl;     return 0; }简单实现

#include <iostream> #include<string> using namespace std; int main() { string s; cin>>s; int i; for(i=s.length()-1;i>=0;i--) cout<<s[i]; cout<<endl; return 0; }

ch4 = ch3 - ch2 + ch1 = '0' - '5' + 'a' = 'a' - 5 = 92 = '\'

太简单的逻辑了，同学要努力啊 #include <iostream.h> #include <string.h> int main () {     char s[255];     cin.getline(s,255);     cout<<"asc:"<<s<<endl;     cout<<"des:";     for(int i=strlen(s)-1;i>=0;i--)         cout<<s[i];     cout<<endl; }