分式加减 .
化简求值 (x-y分之1 - x+y分之1)÷x平方-2xy+y平方分之2y
分式加减 .化简求值 (x-y分之1
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解决时间 2021-05-04 17:37
- 提问者网友：临风不自傲
- 2021-05-03 22:10
最佳答案
- 五星知识达人网友：行路难
- 2021-05-03 23:21
[1/(x-y) - 1/(x+y)]÷2y/(x^2-2xy+y^2)
=[(x+y)/(x+y)(x-y) - (x-y)/(x+y)(x-y)]÷2y/(x-y)^2
=[(x+y - x+y)/(x+y)(x-y)]÷2y/(x-y)^2
=[2y/(x+y)(x-y)]÷2y/(x-y)^2
=2y/(x+y)(x-y)*(x-y)^2/2y
=(x-y)/(x+y)
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