一道Java编程题！

使用5.6.7.8.9
组成一个三位数和一个两位数，并从这样的数中找到两数乘积最大的这个数

要求：
这五个数组成一个各位都不相同的三位数，和一个各位也不相同的两位数，
并且两位数中的任何一位不能和前面的三位数任何一位都相同

public class Caculate {

public static void main(String[] args) {
int[] array=new int[5];
array[0]=5;
array[1]=6;
array[2]=7;
array[3]=8;
array[4]=9;

int max=0;
int a,b,c,d,e;
a=0;
b=0;
c=0;
d=0;
e=0;

for(int i=0;i<array.length;i++){
for(int j=0;j<array.length;j++){
for(int k=0;k<array.length;k++){
for(int z=0;z<array.length;z++){
for(int x=0;x<array.length;x++){
boolean condition=(i!=j&&i!=k&&i!=z&&i!=x&&j!=k&&j!=z&&j!=x&&k!=z&&k!=x&&z!=x);
if(condition){
int temp=(array[i]*100+array[j]*10+array[k])*(array[z]*10+array[x]);
if(temp>max){
max=temp;
a=array[i];
b=array[j];
c=array[k];
d=array[z];
e=array[x];

}
}
}
}
}
}
}

System.out.println("The max number is "+a+b+c+"*"+d+e+" = "+max);

}
}

public class Calculator { private int biggest; private int num1; private int num2;

public static void main(String[] args) { int[] num = { 5, 6, 7, 8, 9 }; Calculator cal = new Calculator(); cal.getBig(num, 0, 4); System.out.println(cal.num1 + "*" + cal.num2 + "=" + cal.biggest); }

private void getBig(int[] num, int low, int high) { if (low == high) { int firstNum = num[0] * 100 + num[1] * 10 + num[2]; int secondNum = num[3] * 10 + num[4]; if (firstNum * secondNum > biggest) { num1 = firstNum; num2 = secondNum; biggest = firstNum * secondNum; } } else { for (int i = low; i <= high; i++) { int tem = num[i]; num[i] = num[low]; num[low] = tem; getBig(num, low + 1, high); tem = num[i]; num[i] = num[low]; num[low] = tem; }

} } }

运行结果：

875*96=84000