C语言问题：定义一个元素是字符串的数组时，能这样定义吗？char month[]={ "dfsdf","edfdf","uyyu"}

C语言问题：定义一个元素是字符串的数组时，能这样定义吗？char month[]={ "dfsdf","edfdf","uyyu"}

////////////楼主的问题是二维数组定义有误///////////////////

dfsdf
edfdf
uyyuy
kljhgj
sdafwewe
Press any key to continue
//方法一 指针数组
#include
main()
{
int i;
char *month[5]={
"dfsdf","edfdf","uyyuy","kljhgj","sdafwewe" };
for(i=0;i<5;i++)
printf("%s\n",month[i]);
}

//二维数组
#include
main()
{
int i;
char month[5][10]={
"dfsdf","edfdf","uyyuy","kljhgj","sdafwewe" };
for(i=0;i<5;i++)
printf("%s\n",month[i]);
}

有疑问请追问 满意记得采纳

数组定义没有问题，但是数组初始化错了，初始化时你并不是给的5个字符，你给的是5个字符串。

main 函数类型？？
int main (void)

char是字符类型不是字符串类型，你存储的是字符串所以要用字符串类型来定义。如过要用char来定义数组的话就要运用二维数组来定义，也就是说你上面的数组定义应该是char month[5][10]={ "dfsdf","edfdf","uyyuy","kljhgj","sdafwewe"};

#include
main()
{
int i;
char month[5][10]={ "dfsdf","edfdf","uyyuy","kljhgj","sdafwewe" }; //是二维字符数组
for(i=0;i<5;i++)
printf("%s\n",month[i]);
getch();
}