-4/(y^4+1)-2/(y^2+1)-1/(y+1)+1/(y-1)=2y/(-1+y^8)
答案:2 悬赏:70 手机版
解决时间 2021-02-14 07:53
- 提问者网友：川水往事
- 2021-02-14 01:00
解方程
最佳答案
- 五星知识达人网友：千杯敬自由
- 2021-02-14 02:18
原方程左边=-4/(y^4+1) -2/(y^2+1) +[1/(y-1) -1/(y+1)]
=-4/(y^4+1) -2/(y^2+1) +[(y+1)-(y-1)]/[(y-1)*(y+1)]
=-4/(y^4+1) -2/(y^2+1) +2/(y^2-1)
=-4/(y^4+1) +2[1/(y^2-1) -1/(y^2+1)]
=-4/(y^4+1) +2[(y^2+1)-(y^2-1)]/[(y^2+1)*(y^2-1)]
=-4/(y^4+1) +4/(y^4-1)
=4[1/(y^4-1) -1/(y^4+1)]
=4[(y^4+1)-(y^4-1)]/[(y^4-1)*(y^4+1)]
=8/(y^8-1)
原方程右边=2y/(-1+y^8)
所以 2y=8
所以 y=4
=-4/(y^4+1) -2/(y^2+1) +[(y+1)-(y-1)]/[(y-1)*(y+1)]
=-4/(y^4+1) -2/(y^2+1) +2/(y^2-1)
=-4/(y^4+1) +2[1/(y^2-1) -1/(y^2+1)]
=-4/(y^4+1) +2[(y^2+1)-(y^2-1)]/[(y^2+1)*(y^2-1)]
=-4/(y^4+1) +4/(y^4-1)
=4[1/(y^4-1) -1/(y^4+1)]
=4[(y^4+1)-(y^4-1)]/[(y^4-1)*(y^4+1)]
=8/(y^8-1)
原方程右边=2y/(-1+y^8)
所以 2y=8
所以 y=4
全部回答
- 1楼网友：白昼之月
- 2021-02-14 03:00
（y-2）（y²+2y）-（y²+1）（y-1）
=(y-2)y(y++2)-（y²+1）（y-1）
=y(y^2-4)-(y^3+y-y^2-1)
=y^2-5y+1
故原式＝1/16-5/4+1=-3/16
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