sql语句什么情况返回集合 什么情况返回数组

sql没有数组类型的，不过你可以自定一个varchar类型的变量，里边装字符串，用逗号分开，然后进行分割就成了数组，

第一步：数组长度的函数

sql code

alter function arrlen(@string varchar(1000),@spacemark varchar(200)) --@string 眼拆分的字符串 @spacemark 分割符 returns int as begin declare @i int set @i = (len(@string) - len(replace(@string,@spacemark,'')))/len(@spacemark) return(@i) end

第二步：按索引值取数组中的数据

sql code

alter function arrlist(@string varchar(8000),@spacemark varchar(8000),@arrstation int) returns varchar(8000) as begin declare @newstring varchar(8000) declare @returnstring varchar(8000) set @newstring = @string declare @i int set @i = 0 if(@arrstation>0 and @arrstation<=dbo.arrlen(@string,@spacemark)) begin while(@i<@arrstation) begin set @newstring = substring(@newstring,charindex(@spacemark,@newstring)+1,len(@newstring)) set @i = @i + 1 end end if(@arrstation<0) begin set @returnstring = '上标越界' end else if(@arrstation<dbo.arrlen(@string,@spacemark)) begin set @returnstring = substring(@newstring,1,charindex(@spacemark,@newstring)-1) end else if(@arrstation=dbo.arrlen(@string,@spacemark)) begin set @returnstring = @newstring end else begin set @returnstring = '下标越界' end return(@returnstring) end

测试程序: declare @a varchar(1000) declare @i int set @i = 0 set @a = 'a,b,c,d,e,f,g,h,i' while(@i <=dbo.arrlen(@a,',')) begin print dbo.arrlist(@a,',',@i) set @i = @i + 1 end