求7/8兀的三角函数
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解决时间 2021-03-10 15:07
- 提问者网友：愿为果
- 2021-03-10 07:02
求7/8兀的三角函数
最佳答案
- 五星知识达人网友：野慌
- 2021-03-10 07:27
sinπ/8 = √{(1-cosπ/4)/2} = √{(1-√2/2)/2} = √(2-√2)/2
cosπ/8 = √{(1+cosπ/4)/2} = √{(1+√2/2)/2} = √(2+√2)/2
tanπ/8 = (1-cosπ/4)/(sinπ/4) = (1-√2/2)/(√2/2) = √2-1
sin7π/8 = sinπ/8 = √(2-√2)/2
c os7π/8 = -cosπ/8 = -√(2+√2)/2
t an7π/8 = -tanπ/8 = 1-√2
cosπ/8 = √{(1+cosπ/4)/2} = √{(1+√2/2)/2} = √(2+√2)/2
tanπ/8 = (1-cosπ/4)/(sinπ/4) = (1-√2/2)/(√2/2) = √2-1
sin7π/8 = sinπ/8 = √(2-√2)/2
c os7π/8 = -cosπ/8 = -√(2+√2)/2
t an7π/8 = -tanπ/8 = 1-√2
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