怎样用C语言程序写出一个字？

答案:6 悬赏:0 手机版

解决时间 2021-02-12 04:00

提问者网友：杀手的诗
2021-02-11 22:14

怎么用C编写程序写出“鉴”字？

就是C语言程序运行之后，屏幕上显示出“鉴”这个字，不要通过连接图片显示出来的那种，要运行之后就能显示出来的，字体最好是彩色渐变色，实在不行蓝色也行

当然，要是运行之后，能显示出一笔一笔写出来（就像用笔一笔一笔写出来那样）的效果那就更好了

恳请高手们帮帮忙，在下万分感谢！！
要Vista系统下，用VC或TC能运行成功的

最佳答案

五星知识达人网友：低血压的长颈鹿
2021-02-11 23:18

本题一个完美的程序如下，程序已在tc2.0和win-tc下运行通过。
说明：如果程序不能运行，请将initgraph(&gdriver,&gmode,"")函数中的""更改为你的TC安装目录。比如你的TC安装目录为D盘的Tools子目录下的TC目录，那么上述语句改为：initgraph(&gdriver,&gmode,"D:\\Tools\\TC");
同时保证在D:\\Tools\\TC目录里有文件EGAVGA.BGI，如果没有从TC安装目录下复制一个过来。万一不行，将本程序复制到你的TC安装目录下再运行。
如还有疑问，给我消息。
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <time.h>
#include <dos.h>
#include <graphics.h>

int main()
{int i,j;
int gdriver=DETECT,gmode;
initgraph(&gdriver,gmode,"");
srand((unsigned)time(NULL));
setbkcolor(0);
setlinestyle(0,0,3);
while(!kbhit())
{setcolor(rand()%16);
line(200,200,200,225);
delay(100000);
line(225,175,225,225);
delay(100000);
line(275,175,250,225);
delay(100000);
line(263,200,300,200);
delay(100000);
line(263,200,275,225);
delay(100000);
line(250,225,200,275);
delay(100000);
line(250,225,300,275);
delay(100000);
line(225,250,275,250);
delay(100000);
line(225,275,275,275);
delay(100000);
line(250,250,250,325);
delay(100000);
line(230,280,250,325);
delay(100000);
line(270,280,250,325);
delay(100000);
line(200,325,300,325);
delay(100000);
for(j=0;j<10;j++)
delay(300000);
cleardevice();
}
getch();
closegraph();
return 0;
}

全部回答

1楼网友：几近狂妄
2021-02-12 02:16

可以找到这个字的ASCII码嘛！然后输出这个ASCII的值！

2楼网友：猎心人
2021-02-12 01:59

汉字的显示，就是显示点阵数据。汉字的编码，就是已经存储在计算机里的点阵数据的编号。这个题，你可以在屏幕逐个描点，以达到想要的效果。描点需要图形库的支持，比如dos下，就有graphic.h 如果你在dos下编程，就用它吧 windows不支持graphic.h图形库因为，windows支持窗口模式的编程

3楼网友：拾荒鲤
2021-02-12 01:26

Win-TC下面有字模工具还有范例，你可以去看一下 #include "Conio.h" #include "graphics.h" #define closegr closegraph void initgr(void) { int gd = DETECT, gm = 0; registerbgidriver(EGAVGA_driver); initgraph(&gd, &gm, ""); } void drawmat(char *mat,int matsize,int x,int y,int color) { int i, j, k, n; n = (matsize - 1) / 8 + 1; for(j = 0; j < matsize; j++) for(i = 0; i < n; i++) for(k = 0;k < 8; k++) if(mat[j * n + i] & (0x80 >> k)) putpixel(x + i * 8 + k, y + j, color); } char jian64S[]={ 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00, 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00, 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00, 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00, 0x00,0x00,0x00,0x00,0x03,0x00,0x00,0x00, 0x00,0x00,0x02,0x00,0x03,0xC0,0x00,0x00, 0x00,0x00,0x03,0x80,0x03,0xC0,0x00,0x00, 0x00,0x00,0x03,0x80,0x03,0x80,0x00,0x00, 0x00,0x18,0x03,0x00,0x07,0x00,0x00,0x00, 0x00,0x1E,0x03,0x00,0x06,0x00,0x00,0x00, 0x00,0x1C,0x03,0x00,0x06,0x00,0x02,0x00, 0x00,0x18,0x03,0x00,0x0C,0x00,0x07,0x00, 0x00,0x18,0x03,0x00,0x08,0x00,0x0F,0x80, 0x00,0x18,0x03,0x00,0x1F,0xFF,0xFF,0xC0, 0x00,0x18,0x03,0x00,0x10,0x00,0x00,0x00, 0x00,0x18,0x03,0x00,0x20,0x00,0x00,0x00, 0x00,0x18,0x03,0x00,0x20,0x10,0x00,0x00, 0x00,0x18,0x03,0x00,0x40,0x08,0x00,0x00, 0x00,0x18,0x03,0x00,0x00,0x06,0x00,0x00, 0x00,0x18,0x03,0x00,0x00,0x03,0x00,0x00, 0x00,0x18,0x03,0x00,0x00,0x03,0x80,0x00, 0x00,0x18,0x03,0x01,0x00,0x01,0xC0,0x00, 0x00,0x18,0x03,0x01,0xC0,0x01,0xE0,0x00, 0x00,0x18,0x03,0x03,0xE0,0x00,0xE0,0x00, 0x00,0x18,0x03,0x07,0x80,0x00,0xE0,0x00, 0x00,0x18,0x03,0x0F,0xC0,0x00,0xE0,0x00, 0x00,0x10,0x00,0x1E,0x20,0x00,0x40,0x00, 0x00,0x00,0x00,0x3C,0x10,0x00,0x00,0x00, 0x00,0x00,0x00,0x78,0x08,0x00,0x00,0x00, 0x00,0x00,0x00,0xF0,0x04,0x00,0x00,0x00, 0x00,0x00,0x01,0xC0,0x03,0x00,0x00,0x00, 0x00,0x00,0x03,0x80,0x01,0x80,0x00,0x00, 0x00,0x00,0x07,0x00,0x00,0xE0,0x00,0x00, 0x00,0x00,0x1C,0x00,0x00,0x78,0x00,0x00, 0x00,0x00,0x38,0x00,0x00,0x3E,0x00,0x00, 0x00,0x00,0xE0,0x00,0x01,0x0F,0xC0,0x00, 0x00,0x01,0xC0,0x00,0x03,0x87,0xF8,0x00, 0x00,0x07,0x07,0xFF,0xFF,0xC1,0xFF,0xF0, 0x00,0x1C,0x02,0x01,0x80,0x00,0x7F,0xF0, 0x00,0x70,0x00,0x01,0x80,0x00,0x1F,0x80, 0x01,0xC0,0x00,0x01,0x80,0x00,0x07,0x80, 0x06,0x00,0x00,0x01,0x80,0x00,0x00,0x00, 0x00,0x00,0x00,0x01,0x80,0x00,0x80,0x00, 0x00,0x00,0x00,0x01,0x80,0x01,0x80,0x00, 0x00,0x00,0x00,0x01,0x80,0x03,0xC0,0x00, 0x00,0x03,0xFF,0xFF,0xFF,0xFF,0xE0,0x00, 0x00,0x00,0x00,0x01,0x80,0x00,0x00,0x00, 0x00,0x00,0x00,0x01,0x80,0x00,0x00,0x00, 0x00,0x00,0x00,0x01,0x80,0x18,0x00,0x00, 0x00,0x00,0x10,0x01,0x80,0x1E,0x00,0x00, 0x00,0x00,0x08,0x01,0x80,0x1C,0x00,0x00, 0x00,0x00,0x0C,0x01,0x80,0x38,0x00,0x00, 0x00,0x00,0x0E,0x01,0x80,0x20,0x00,0x00, 0x00,0x00,0x06,0x01,0x80,0x40,0x00,0x00, 0x00,0x00,0x06,0x01,0x80,0x00,0x00,0x00, 0x00,0x00,0x04,0x01,0x80,0x80,0x02,0x00, 0x00,0x00,0x00,0x01,0x80,0x00,0x07,0x00, 0x00,0x00,0x00,0x01,0x80,0x00,0x0F,0x80, 0x01,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xC0, 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00, 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00, 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00, 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00, 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00, }; int main(void) { int i, j; initgr(); drawmat(jian64S, 64, 100, 125, BLUE); getch(); closegr(); return 0; }

4楼网友：荒野風
2021-02-12 01:17

以下代码实现字符从右到左循环滚动. c语言控制台程序 #include #include #include int main() { char str[100] = "hello world! good bye!"; int i,j; for(i=0;i

5楼网友：独钓一江月
2021-02-12 00:18

……几个途径啦其一，其实字也是图片的一种，平时看到的字都是通过字体库显示出来的所以要达到效果应该需要看有没相关库函数可以调用字体库的其二，完全自己搞定就好啦，显示个字也不是很难啦说到底就是点阵显示而已嘛。可以自己看看怎么显示点阵，或者最简单去网上搜下鉴这个字的点阵是怎么排的。然后用符号把鉴这个字的点阵输出就可以了如果要一笔一划写出来，再用时间函数就好啦至于彩色，不会啦~

我要举报

如以上问答信息为低俗、色情、不良、暴力、侵权、涉及违法等信息，可以点下面链接进行举报！