x+1/x乘以(2x/x+1)^2-(1/x-1 - 1/x+1) 现在就要，快快快~
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解决时间 2021-02-27 20:19
- 提问者网友：
- 2021-02-26 22:43
x+1/x乘以(2x/x+1)^2-(1/x-1 - 1/x+1) 现在就要，快快快~
最佳答案
- 五星知识达人网友：旧脸谱
- 2021-02-27 00:06
您好：
x+1/x乘以(2x/x+1)^2-(1/x-1 - 1/x+1)
=2/（x+1）-1/(x-1)+1/(x+1)
=1/(x+1)-1/(x-1)
=(x-1-x-1)/（x+1）(x-1)
=-2/(x²-1)
不明白，可以追问
如有帮助，记得采纳，谢谢
祝学习进步！
x+1/x乘以(2x/x+1)^2-(1/x-1 - 1/x+1)
=2/（x+1）-1/(x-1)+1/(x+1)
=1/(x+1)-1/(x-1)
=(x-1-x-1)/（x+1）(x-1)
=-2/(x²-1)
不明白，可以追问
如有帮助，记得采纳，谢谢
祝学习进步！
全部回答
- 1楼网友：怙棘
- 2021-02-27 00:39
(x+1)/x乘以[\(2x/(x+1)]^2-[1/(x-1) - 1/(x+1)]
=[(x+1)(4x)/(x+1)]^2-[2/(x-1)(x+1)]
=[4x(x+1)(x-1)-2(x+1)(x-1)]/(x+1)^2(x-1)
=[4x²-4x-2x+2]/(x+1)(x-1)
=2(2x-1)(x-1)/(x+1)(x-1)
=2(2x-1)/(x+1)
=[(x+1)(4x)/(x+1)]^2-[2/(x-1)(x+1)]
=[4x(x+1)(x-1)-2(x+1)(x-1)]/(x+1)^2(x-1)
=[4x²-4x-2x+2]/(x+1)(x-1)
=2(2x-1)(x-1)/(x+1)(x-1)
=2(2x-1)/(x+1)
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