从键盘输入正整数n,计算并输出1到n的和,c语言谢谢
答案:6 悬赏:60 手机版
解决时间 2021-03-24 02:23
- 提问者网友：泪痣哥哥
- 2021-03-23 04:59
从键盘输入正整数n,计算并输出1到n的和,c语言谢谢
最佳答案
- 五星知识达人网友：渡鹤影
- 2021-03-23 05:12
#include "stdio.h"
int main()
{
int n,sum=0,i;
printf("Please input a number:\n");
scanf("%d",&n);
for(i=1;i<=n;i++)
sum+=i;
printf("The sum is %d.\n",sum);
}
int main()
{
int n,sum=0,i;
printf("Please input a number:\n");
scanf("%d",&n);
for(i=1;i<=n;i++)
sum+=i;
printf("The sum is %d.\n",sum);
}
全部回答
- 1楼网友：街头电车
- 2021-03-23 10:29
#include
int main(){
int n,i,sum=0;
scanf("%d",&n);
for(i=0;i<=n;i++){
sum=sum+i;
}
printf("%d",sum);
return 0;
}
int main(){
int n,i,sum=0;
scanf("%d",&n);
for(i=0;i<=n;i++){
sum=sum+i;
}
printf("%d",sum);
return 0;
}
- 2楼网友：鱼芗
- 2021-03-23 09:15
#iiclude
main(){
int i,n,s=0;
scanf("%d",&n);
for (i=1;i<=n;i++) s+=i;
printf("%d",s);
}
main(){
int i,n,s=0;
scanf("%d",&n);
for (i=1;i<=n;i++) s+=i;
printf("%d",s);
}
- 3楼网友：長槍戰八方
- 2021-03-23 07:57
这个很简单，不需要循环
#include "stdio.h"
int main()
{
int n,sum=0;
printf("Please input a number:\n");
scanf("%d",&n);
sum = (n *(n+1))/2;
printf("The sum is %d.\n",sum);
return 0;
}
#include "stdio.h"
int main()
{
int n,sum=0;
printf("Please input a number:\n");
scanf("%d",&n);
sum = (n *(n+1))/2;
printf("The sum is %d.\n",sum);
return 0;
}
- 4楼网友：持酒劝斜阳
- 2021-03-23 07:21
#iiclude
main(){
int i,n,s=0;
scanf("%d",&n);
for (i=1;i<=n;i++) s+=i;
printf("%d",s);
}
main(){
int i,n,s=0;
scanf("%d",&n);
for (i=1;i<=n;i++) s+=i;
printf("%d",s);
}
- 5楼网友：梦中风几里
- 2021-03-23 05:45
#include
void main()
{
int i,n,s=0;
scanf("%d",&n);
for (i=1;i<=n;i++)
{
s+=i;
}
printf("%d",s);
}
void main()
{
int i,n,s=0;
scanf("%d",&n);
for (i=1;i<=n;i++)
{
s+=i;
}
printf("%d",s);
}
我要举报
如以上问答信息为低俗、色情、不良、暴力、侵权、涉及违法等信息，可以点下面链接进行举报！
大家都在看
推荐资讯