已知A-B=-3,c+d=2,求(b+c)-(a-d)的值
着急呀!!!
∵a-b=-3,c+d=2,
∴(b+c)-(a-d)=-(a-b)+(c+d)=3+2=5
a-b=-3
所以b-a=3
(b+c)-(a-d)=c+d+b-a=2+3=5
整理原式得
(c + d) - (a - b) = 2 - (-3) = 5