已知x的平方+x-1=0,求x(1-1-x分之2)除以(x+1)-x平方-2x+1分之x(x的平方-1)
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解决时间 2021-02-09 16:27
- 提问者网友：美人性情
- 2021-02-09 00:21
已知x的平方+x-1=0,求x(1-1-x分之2)除以(x+1)-x平方-2x+1分之x(x的平方-1)
最佳答案
- 五星知识达人网友：千夜
- 2021-02-09 01:15
x[1-2/(1-x)]/(x+1)-x(x-1)/(x-2x+1)
=(x+1)/[(x-1)(x+1)]-x(x+1)/(x-1)
=1/(x-1)-x(x+1)/(x-1)
=-(x+x-1)/(x-1)
=0
=(x+1)/[(x-1)(x+1)]-x(x+1)/(x-1)
=1/(x-1)-x(x+1)/(x-1)
=-(x+x-1)/(x-1)
=0
全部回答
- 1楼网友：一把行者刀
- 2021-02-09 01:53
x[1-2/(1-x)]/(x+1)-x(x²-1)/(x²-2x+1)
=(x+1)/[(x-1)(x+1)]-x(x+1)/(x-1)
=1/(x-1)-x(x+1)/(x-1)
=-(x²+x-1)/(x-1)
=0
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