C++ 使用new运算符申请两个匿名对象

#include // 包含头文件iostream
using namespace std; // 使用命名空间std
class Engineer
{
public:
Engineer();
Engineer(int pId,char* pName,char* pPosition);
void setEngineer(int pId,char* pName,char* pPosition);
~Engineer();
void printEngineer();
private:
int Id;
char* Name;
char* Position;
};
Engineer::Engineer ()
{
int i=1;
}
Engineer:: Engineer (int pId,char* pName,char* pPosition)
{
int j=1;
}
void Engineer:: setEngineer (int pId, char* pName, char* pPosition)
{
Id=pId;
Name=new char[strlen(pName)+1];
if(Name!=0)
strcpy(Name,pName);
Position=new char[strlen(pPosition)+1];
if(Position!=0)
strcpy(Position,pPosition); //Engineer的成员函数setEngineer的实现
}
Engineer::~ Engineer ()
{
int k=1;//Engineer的析构函数的实现
}
void Engineer::printEngineer ()
{
cout<<"Name:"<}
int main()
{
Engineer e[4];
e[0].setEngineer(1001,"王含","讲师"); //这些信息换成班上同学
e[1].setEngineer(1002,"张青","讲师");
e[2].setEngineer(1003,"赵菁","副教授");
e[3].setEngineer(1004,"姚琳","教授");
Engineer * pE1 =new Engineer (1005,"方伟","副教授");
Engineer * pE2 =new Engineer (1006,"黄玲","教授");

e[0].printEngineer ();
e[1]. printEngineer ();
e[2]. printEngineer ();
e[3]. printEngineer ();

pE1->printEngineer ();
pE2->printEngineer ();

delete pE1, pE2;
return 0;
}
到Engineer * pE1 =new Engineer (1005,"方伟","副教授");程序就运行不了了，不是很懂Engineer * pE1 =new Engineer (1005,"方伟","副教授");pE1->printEngineer ();
这两句，求解答。

首先我真的想打死你，简直在逗我。试了下程序，老说访问越界。下面是解释。
//创建一个指向Engineer对象的指针，new是在堆区创建对象，并返回地址。创建对象会先调
//构造函数
Engineer * pE1 =new Engineer (1005,"方伟","副教授");
//pE1 ->等价于 （*pE1）. 表示访问pE1指向的对象的printEnginrer();函数成员
pE1->printEngineer ();

然后你为什么会错？因为你创建Engineer e[4] 对象数组中的对象是空的，调用无参构造函数
然后你e[0].setEngineer(1001,"王含","讲师"); 调用的成员函数赋值。

new只会调用构造函数（3参），而你的构造函数没写赋值语句或者初始化列表。
也就说你调用new 并没有给指向对象赋值， pE1,pE2对象的数据成员是空的。
所以访问越界
最后说一句，数据成员最好是private。

当然不对了，赋值就是从一个对象赋值给另一个，参数只能是一个本类对象