1.-2.7x56+7.9x(-56)+6x5.6
-(1/90).呢那么;nx(n+1)呢?
(-1/2)-(1/6)-(1/12)-⋯?告诉我过程,为什么这么做?
1x2+2x3+3x4+⋯,请问1x2+2x3+3x4+⋯+100x101等于多少
初一的数学题,用简便方法计算的题目
答案:6 悬赏:80 手机版
解决时间 2021-02-08 08:05
- 提问者网友:骑士
- 2021-02-07 21:38
最佳答案
- 五星知识达人网友:街头电车
- 2021-02-07 22:23
-2.7x56+7.9x(-56)+6x5.6
=-2.7x56-7.9x56+(6÷10)x(10x5.6)
=-2.7x56-7.9x56+0.6x56
=56x(-2.7-7.9+0.6)
=56x(-10)
=-560
=-2.7x56-7.9x56+(6÷10)x(10x5.6)
=-2.7x56-7.9x56+0.6x56
=56x(-2.7-7.9+0.6)
=56x(-10)
=-560
全部回答
- 1楼网友:山河有幸埋战骨
- 2021-02-08 04:30
-2.7x56+7.9x(-56)+6x5.6
=0.6x56-2.7x56-7.9x56
=56x(0.6-2.7-7.9)
=56x(-10)
=-560
- 2楼网友:神的生死簿
- 2021-02-08 03:00
原式=-56*(2.7+7.9-0.6)=-56*10=-560
1x2+2x3+3x4+⋯+100x101
可以看出每2项合并后的规律,原式=2(2×2+4×4+6×6+。。。。+100×100)
=2(2^2+4^2+6^2+.....+100^2)
=2*(100*51*101)/3=343400
- 3楼网友:躲不过心动
- 2021-02-08 02:19
(3/5-1/2-7/12)乘(60*3/7-60*1/7+60*5/7)
=(3/5-1/2-7/12)乘(3/7-1/7+5/7)×60
=(3/5-1/2-7/12)×1×60
=3/5×60-1/2×60-7/12×60
=36-30-35
= -29
13除1.5-0.34除3又1/3+1/3除1/13-0.34除1又2/5
=13除3/2-0.34除10/3+1/3除1/13-0.34除7/5
=13×2/3-0.34×3/10+1/3×13-0.34×5/7
=13×2/3+1/3×13-0.34×3/10-0.34×5/7
=13×(2/3+1/3)-0.34×(3/10+5/7)
=13-0.34×71/70
-149又3/40乘20
=(-149-3/40)乘20
= -298-3/2
= -299-1/2
=-299又1/2
99又24/25乘(-5)
=99×(-5)+24/25×(-5)
= -495-24/5
= -499-4/5
= -499又4/5
- 4楼网友:玩家
- 2021-02-08 00:52
-2.7x56+7.9x(-56)+6x5.6
=-2.7×5.6×10+7.9×(-5.6)×10+6×5.6
=-27*5.6-79×5.6+6×5.6
=5.6×(-27-79+6)
=5.6×(-100)
= - 560
- 5楼网友:逃夭
- 2021-02-07 23:37
2)-(1/3
当n=100时,就有;(2×3)+1/+n)
=(1²9-1/.7+7;3+1/10]
=-(1-1/.9-0;(1×2)+1/3=343400
(-1/+…+n².6
=-(2.7×56+7.9×(-56)+6×5.6
=-2;4+…+1/(3×4)+…+1/+1)+(2²+3)+…+(n²-2;+2)+(3².6)×56
=-10×56
=-560
1×2+2×3+3×4+…+n(n+1)
=(1²3-1/.7×56-7.9×56+0:1×2+2×3+3×4+…+100×101=100×101×102/.6×5;2+1/12)-…-(1/90)
=-(1/2+1/6+1/12+…+1/)+(1+2+3+…+n)
=n(n+1)(2n+1)/6+n(n+1)/2-1/2
=n(n+1)/6×(2n+1+3)
=n(n+1)(n+2)/90)
=-[1/6)-(1/(9×10)]
=-[1-1/+2²+3²
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