x^4-6x^2-7x-6怎么饮食分解
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解决时间 2021-02-19 03:57
- 提问者网友：低吟詩仙的傷
- 2021-02-18 17:32
x^4-6x^2-7x-6怎么饮食分解
最佳答案
- 五星知识达人网友：鱼忧
- 2021-02-18 19:03
原式=x^4-4x²-2x²-7x-6
=x²(x²-4)-(2x²+7x+6)
=x²(x+2)(x-2)-(x+2)(2x+3)
=(x+2)(x³-2x²-2x-3)
=(x+2)[(x³-3x²)+(x²-2x-3)]
=(x+2)[x²(x-3)+(x+1)(x-3)]
=(x+2)(x-3)(x²+x+1)
=x²(x²-4)-(2x²+7x+6)
=x²(x+2)(x-2)-(x+2)(2x+3)
=(x+2)(x³-2x²-2x-3)
=(x+2)[(x³-3x²)+(x²-2x-3)]
=(x+2)[x²(x-3)+(x+1)(x-3)]
=(x+2)(x-3)(x²+x+1)
全部回答
- 1楼网友：撞了怀
- 2021-02-18 20:32
=x^2(x^2-4)-2x^2-7x-6
=x^2(x+2)(x-2)-(2x+3)(x+2)
=(x+2)[x^2(x-2)-(2x+3)]
=(x+2)(x^3-2x^2-2x-3)
=(x+2)[x^2(x-3)+x^2-2x-3]
=(x+2)[x^2(x-3)+(x+1)(x-3)]
=(x+2)(x-3)(x^2+x+1)
=x^2(x+2)(x-2)-(2x+3)(x+2)
=(x+2)[x^2(x-2)-(2x+3)]
=(x+2)(x^3-2x^2-2x-3)
=(x+2)[x^2(x-3)+x^2-2x-3]
=(x+2)[x^2(x-3)+(x+1)(x-3)]
=(x+2)(x-3)(x^2+x+1)
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