解线性方程组 x1+2x2+3x3+4x4=5 2x1+4x2+4x3+6x4=8 -x1-2x2-
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解决时间 2021-02-23 12:44
- 提问者网友：末路
- 2021-02-22 22:02
解线性方程组 x1+2x2+3x3+4x4=5 2x1+4x2+4x3+6x4=8 -x1-2x2-
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- 五星知识达人网友：傲气稳了全场
- 2021-02-22 22:32
x1+2x2+3x3+4x4=5 (1) 2x1+4x2+4x3+6x4=8 (2)-x1-2x2- x3-2x4=-3 (3)(1)+(3)2x1+4x2+4x3+6x4=8 = equation(2)Rank of system of equtions = 2(1)+2(3)-x1-2x2+x3=-1x3= x1+2x2-1 (4)sub (4) into (3)-x1-2x2- (x1+2x2-1)-2x4=-3x4= -x1-2x2 +2solution of system of equations(x1,x2,x1+2x2-1,-x1-2x2 +2)x1,x2属于R======以下答案可供参考======供参考答案1:x1+2x2+3x3+4x4=5 (1) 2x1+4x2+4x3+6x4=8 (2)-x1-2x2- x3-2x4=-3 (3)(1)+(3)2x1+4x2+4x3+6x4=8 = equation(2)Rank of system of equtions = 2(1)+2(3)-x1-2x2+x3=-1x3= x1+2x2-1 (4)sub (4) into (3)-x1-2x2- (x1+2x2-1)-2x4=-3x4= -x1-2x2 +2(x1,x2, x1+2x2-1, -x1-2x2 +2)x1,x2属于R 祝你学习进步！
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- 1楼网友：一叶十三刺
- 2021-02-22 23:38
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