化简求值:(a-3分之a+2加a^2-a-6分之a^2-4)除以a-3分之a+1,其中a=-2分之1
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解决时间 2021-02-15 13:58
- 提问者网友：富士山上尢
- 2021-02-15 04:10
化简求值:(a-3分之a+2加a^2-a-6分之a^2-4)除以a-3分之a+1,其中a=-2分之1
最佳答案
- 五星知识达人网友：拾荒鲤
- 2021-02-15 04:23
:(a-3分之a+2加a^2-a-6分之a^2-4)除以a-3分之a+1,
=[(a+2)/(a-3)+(a²-4)/(a²-a-6)]÷(a+1)/(a-3)
=[(a+2)/(a-3)+(a-2)(a+2)/(a+2)(a-3)]×(a-3)/(a+1)
=[(a+2)/(a-3)+(a-2)/(a-3)]×(a-3)/(a+1)
=2a/(a-3)×(a-3)/(a+1)
=2a/(a+1) 其中a=-2分之1
=2*(-1/2)/(-1/2+1)
=-1/(-1/2)
=2
=[(a+2)/(a-3)+(a²-4)/(a²-a-6)]÷(a+1)/(a-3)
=[(a+2)/(a-3)+(a-2)(a+2)/(a+2)(a-3)]×(a-3)/(a+1)
=[(a+2)/(a-3)+(a-2)/(a-3)]×(a-3)/(a+1)
=2a/(a-3)×(a-3)/(a+1)
=2a/(a+1) 其中a=-2分之1
=2*(-1/2)/(-1/2+1)
=-1/(-1/2)
=2
全部回答
- 1楼网友：思契十里
- 2021-02-15 06:07
:(a-3分之a+2加a^2-a-6分之a^2-4)除以a-3分之a+1
=[(a+2)/(a-3)+(a+2)(a-2)/(a-3)(a+2)]×(a-3)/(a+1)
=4/(a-3)×(a-3)/(a+1)
=4/(a+1)
=4/(-1/2+1)
=8
- 2楼网友：逐風
- 2021-02-15 04:32
=a/(a-3)-(a+6)/[a(a-3)]+3/a
=(a²-a-6+3a-9)/[a(a-3)]
=(a²+2a-15)/[a(a-3)]
=(a-3)(a+5)/[a(a-3)]
=(a+5)/a
=1+5/a；把a=3/2代入
=1+10/3
=13/3
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