易语言全P源码怎么制作成全P摸版呢

缺少1.8.0的全P摸版 但是找到了1.8.0的全P源码请高手指点

这是我亲自写的，没有按照你定义的结构体和函数名来写，已经实现创建，相加，相乘，输出了，插入的话你自己完成吧

输入方法：
1 2 1 1 0 0
1 2 1 1 0 0

#include<stdio.h>
#include<stdlib.h>
#include<malloc.h>

typedef struct polynomial
{
int coef,ex;
struct polynomial *next;
}POLY;

POLY *create_poly(void);

POLY *add_poly(POLY *,POLY *);

POLY *mul_poly(POLY *,POLY *);

void print_poly(POLY *);


int main(void)
{
POLY *heada=NULL,*headb=NULL,*headsum=NULL,*headmul=NULL;
printf("create the first multinomial:\n");
heada=create_poly();
printf("create the second multinomial:\n");
headb=create_poly();
printf("The first multinomial:\n");
print_poly(heada);
printf("The second multinomial:\n");
print_poly(headb);
headsum=add_poly(heada,headb);
printf("The sum multinomial:");
print_poly(headsum);
headmul=mul_poly(heada, headb);
printf("The mul multinomial:");
print_poly(headmul);
return 0;
}


//创建
POLY *create_poly()
{
int iA=0,iE=0;
POLY *head=NULL,*s=NULL,*r=NULL;
head=(POLY *)malloc(sizeof(POLY));
r=head;
printf("please input coef and exponent:\n");
scanf("%d%d",&iA,&iE);
while(iA != 0)
{
s=(POLY *)malloc(sizeof(POLY));
s->coef=iA,s->ex=iE;
r->next=s;
r=s;
scanf("%d%d",&iA,&iE);
}
r->next=NULL;
return head;
}


//相加
POLY *add_poly(POLY *p1, POLY *p2) //多项式相加

{

POLY *head, *tmp, *s;

int value;


p1=p1->next;

p2=p2->next;

head=tmp=(POLY*)malloc(sizeof(POLY));

head->next=NULL;

while(p1 && p2)

{

if(p1->ex == p2->ex)

{

value=p1->coef+p2->coef;

if(value != 0)

{

s=(POLY *)malloc(sizeof(POLY));

s->coef=value;

s->ex=p1->ex;

s->next=NULL;