把下列各式通分 5x-20分之x+5,x的二次方-9x+20分之5,5-x分之x
答案:2 悬赏:50 手机版
解决时间 2021-02-09 23:51
- 提问者网友：遁入空寂
- 2021-02-09 04:18
把下列各式通分 5x-20分之x+5,x的二次方-9x+20分之5,5-x分之x
最佳答案
- 五星知识达人网友：野味小生
- 2021-02-09 05:02
解：5x-20=5(x-4)
x²-9x+20=(x-4)(x-5)
5-x=-(x-5)
最简公分母是5(x-4)(x-5)
5x-20分之x+5=(x+5)/(5x-20)
=(x+5)/[5(x-4)]
=(x+5)(x-5)/[5(x-4)(x-5)]
x²-9x+20分之5=5/(x²-9x+20)
=5/[(x-4)(x-5)]
=25/[5(x-4)(x-5)]
5-x分之x=x/(5-x)
=-x/(x-5)
=-5x(x-4)/[5(x-4)(x-5)]
x²-9x+20=(x-4)(x-5)
5-x=-(x-5)
最简公分母是5(x-4)(x-5)
5x-20分之x+5=(x+5)/(5x-20)
=(x+5)/[5(x-4)]
=(x+5)(x-5)/[5(x-4)(x-5)]
x²-9x+20分之5=5/(x²-9x+20)
=5/[(x-4)(x-5)]
=25/[5(x-4)(x-5)]
5-x分之x=x/(5-x)
=-x/(x-5)
=-5x(x-4)/[5(x-4)(x-5)]
全部回答
- 1楼网友：迷人又混蛋
- 2021-02-09 06:21
=(99-x)/20
=4x^2-36x+1
=5追问这是初二数学分式通分追答=(99x-5)/20
=4x^2-36x+1
=5追问算我没问
=4x^2-36x+1
=5追问这是初二数学分式通分追答=(99x-5)/20
=4x^2-36x+1
=5追问算我没问
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