PID编程的实例!
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解决时间 2021-11-16 15:34
- 提问者网友:听门外雪花风
- 2021-11-15 22:49
PID编程的实例!
最佳答案
- 五星知识达人网友:天凉才是好个秋
- 2021-11-16 00:13
C语言实现PID算法
BC31 TC30 编译过,可运行。
#include
#include
struct _pid {
int pv;
int sp;
float integral;
float pgain;
float igain;
float dgain;
int deadband;
int last_error;
};
struct _pid warm,*pid;
int process_point, set_point,dead_band;
float p_gain, i_gain, d_gain, integral_val,new_integ;;
void pid_init(struct _pid *warm, int process_point, int set_point)
{
struct _pid *pid;
pid = warm;
pid->pv = process_point;
pid->sp = set_point;
}
void pid_tune(struct _pid *pid, float p_gain, float i_gain, float d_gain, int dead_band)
{
pid->pgain = p_gain;
pid->igain = i_gain;
pid->dgain = d_gain;
pid->deadband = dead_band;
pid->integral= integral_val;
pid->last_error=0;
}
void pid_setinteg(struct _pid *pid,float new_integ)
{
pid->integral = new_integ;
pid->last_error = 0;
}
void pid_bumpless(struct _pid *pid)
{
pid->last_error = (pid->sp)-(pid->pv);
}
USAGE #include "control.h"*/
float pid_calc(struct _pid *pid)
{
int err;
float pterm, dterm, result, ferror;
err = (pid->sp) - (pid->pv);
if (abs(err) > pid->deadband)
{
ferror = (float) err;
pterm = pid->pgain * ferror;
if (pterm > 100 || pterm < -100)
{
pid->integral = 0.0;
} else {
pid->integral += pid->igain * ferror;
if (pid->integral > 100.0)
{
pid->integral = 100.0;
} else if (pid->integral < 0.0) pid->integral = 0.0;
}
dterm = ((float)(err - pid->last_error)) * pid->dgain;
result = pterm + pid->integral + dterm;
} else result = pid->integral;
pid->last_error = err;
return (result);
}
void main(void)
{
float display_value;
int count=0;
pid = &warm;
// printf("Enter the values of Process point, Set point, P gain, I gain, D gain \n");
// scanf("%d%d%f%f%f", &process_point, &set_point, &p_gain, &i_gain, &d_gain);
process_point = 30;
set_point = 40;
p_gain = (float)(5.2);
i_gain = (float)(0.77);
d_gain = (float)(0.18);
dead_band = 2;
integral_val =(float)(0.01);
printf("The values of Process point, Set point, P gain, I gain, D gain \n");
printf(" %6d %6d %4f %4f %4f\n", process_point, set_point, p_gain, i_gain, d_gain);
printf("Enter the values of Process point\n");
while(count<=20)
{
scanf("%d",&process_point);
pid_init(&warm, process_point, set_point);
pid_tune(&warm, p_gain,i_gain,d_gain,dead_band);
pid_setinteg(&warm,0.0); //pid_setinteg(&warm,30.0);
//Get input value for process point
pid_bumpless(&warm);
// how to display output
display_value = pid_calc(&warm);
printf("%f\n", display_value);
//printf("\n%f%f%f%f",warm.pv,warm.sp,warm.igain,warm.dgain);
count++;
}
}
BC31 TC30 编译过,可运行。
#include
#include
struct _pid {
int pv;
int sp;
float integral;
float pgain;
float igain;
float dgain;
int deadband;
int last_error;
};
struct _pid warm,*pid;
int process_point, set_point,dead_band;
float p_gain, i_gain, d_gain, integral_val,new_integ;;
void pid_init(struct _pid *warm, int process_point, int set_point)
{
struct _pid *pid;
pid = warm;
pid->pv = process_point;
pid->sp = set_point;
}
void pid_tune(struct _pid *pid, float p_gain, float i_gain, float d_gain, int dead_band)
{
pid->pgain = p_gain;
pid->igain = i_gain;
pid->dgain = d_gain;
pid->deadband = dead_band;
pid->integral= integral_val;
pid->last_error=0;
}
void pid_setinteg(struct _pid *pid,float new_integ)
{
pid->integral = new_integ;
pid->last_error = 0;
}
void pid_bumpless(struct _pid *pid)
{
pid->last_error = (pid->sp)-(pid->pv);
}
USAGE #include "control.h"*/
float pid_calc(struct _pid *pid)
{
int err;
float pterm, dterm, result, ferror;
err = (pid->sp) - (pid->pv);
if (abs(err) > pid->deadband)
{
ferror = (float) err;
pterm = pid->pgain * ferror;
if (pterm > 100 || pterm < -100)
{
pid->integral = 0.0;
} else {
pid->integral += pid->igain * ferror;
if (pid->integral > 100.0)
{
pid->integral = 100.0;
} else if (pid->integral < 0.0) pid->integral = 0.0;
}
dterm = ((float)(err - pid->last_error)) * pid->dgain;
result = pterm + pid->integral + dterm;
} else result = pid->integral;
pid->last_error = err;
return (result);
}
void main(void)
{
float display_value;
int count=0;
pid = &warm;
// printf("Enter the values of Process point, Set point, P gain, I gain, D gain \n");
// scanf("%d%d%f%f%f", &process_point, &set_point, &p_gain, &i_gain, &d_gain);
process_point = 30;
set_point = 40;
p_gain = (float)(5.2);
i_gain = (float)(0.77);
d_gain = (float)(0.18);
dead_band = 2;
integral_val =(float)(0.01);
printf("The values of Process point, Set point, P gain, I gain, D gain \n");
printf(" %6d %6d %4f %4f %4f\n", process_point, set_point, p_gain, i_gain, d_gain);
printf("Enter the values of Process point\n");
while(count<=20)
{
scanf("%d",&process_point);
pid_init(&warm, process_point, set_point);
pid_tune(&warm, p_gain,i_gain,d_gain,dead_band);
pid_setinteg(&warm,0.0); //pid_setinteg(&warm,30.0);
//Get input value for process point
pid_bumpless(&warm);
// how to display output
display_value = pid_calc(&warm);
printf("%f\n", display_value);
//printf("\n%f%f%f%f",warm.pv,warm.sp,warm.igain,warm.dgain);
count++;
}
}
全部回答
- 1楼网友:轻雾山林
- 2021-11-16 01:40
编程的实例
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