VB确定要继续循环一
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解决时间 2021-11-16 22:49
- 提问者网友:你独家记忆
- 2021-11-16 11:49
VB确定要继续循环一
最佳答案
- 五星知识达人网友:旧脸谱
- 2021-11-16 13:08
Const nn = 100
Dim a%(nn), s%
Sub comb(ByVal n%, ByVal k%)
Dim i%, j%
For i = n To k Step -1
a(k) = i
If k > 1 Then
comb i - 1, k - 1
Else
s = s + 1
For j = a(0) To 1 Step -1
Debug.Print Chr(a(j) + 96);
Next
Debug.Print " ";
If s Mod 10 = 0 Then Debug.Print
End If
Next
End Sub
Sub main()
Dim ms%, ns%
s = 0
ns = InputBox("ns")
ms = InputBox("ms")
a(0) = ms
comb ns, ms
Debug.Print vbCrLf; "C("; ns; ","; ms; ")="; s
End Sub
Dim a%(nn), s%
Sub comb(ByVal n%, ByVal k%)
Dim i%, j%
For i = n To k Step -1
a(k) = i
If k > 1 Then
comb i - 1, k - 1
Else
s = s + 1
For j = a(0) To 1 Step -1
Debug.Print Chr(a(j) + 96);
Next
Debug.Print " ";
If s Mod 10 = 0 Then Debug.Print
End If
Next
End Sub
Sub main()
Dim ms%, ns%
s = 0
ns = InputBox("ns")
ms = InputBox("ms")
a(0) = ms
comb ns, ms
Debug.Print vbCrLf; "C("; ns; ","; ms; ")="; s
End Sub
全部回答
- 1楼网友:西风乍起
- 2021-11-16 13:55
Const maxn = 100
Dim a(maxn) As Integer
Dim s As Integer
Function comb(n As Integer, k As Integer)
Dim i As Integer, j As Integer
For i = n To k Step -1
a(k) = i
If k > 1 Then
comb i - 1, k - 1
Else
s = s + 1
For j = a(0) To 1 Step -1
Print Chr(a(j) + 96);
Next
Print " ";
If s Mod 10 = 0 Then Print
End If
Next
comb = s
End Function
Private Sub Command1_Click()
Dim ms As Integer, ns As Integer
ns = InputBox("input n:")
ms = InputBox("inpur m:")
a(0) = ms
comb ns, ms
Print
Print "C("; ns; ","; ms; ")="; s
End Sub
Dim a(maxn) As Integer
Dim s As Integer
Function comb(n As Integer, k As Integer)
Dim i As Integer, j As Integer
For i = n To k Step -1
a(k) = i
If k > 1 Then
comb i - 1, k - 1
Else
s = s + 1
For j = a(0) To 1 Step -1
Print Chr(a(j) + 96);
Next
Print " ";
If s Mod 10 = 0 Then Print
End If
Next
comb = s
End Function
Private Sub Command1_Click()
Dim ms As Integer, ns As Integer
ns = InputBox("input n:")
ms = InputBox("inpur m:")
a(0) = ms
comb ns, ms
Print "C("; ns; ","; ms; ")="; s
End Sub
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