计算[(1-log(6)3)^2+log(6)2 *log(6)18]/log(6)4
1-log(6)3=log(6)(6/3)=log(6)2
log(6)18=log(6)(6*3)=1+log(6)3=1+log(6)(6/2)=1+1-log(6)2=2-log(6)2
(1-log(6)3)^2=[log(6)2]^2
log(6)2*log(6)18=2log(6)2-[log(6)2]^2
原式={[log(6)2]^2+2log(6)2-[log(6)2]^2}/log(6)4=[2log(6)2]/log(6)4=1