已知数列an,a1=2,an+1(n+1是a右下角的注脚）=an+3n+2,则an=多少?

已知数列an,a1=2,an+1(n+1是a右下角的注脚）=an+3n+2,则an=多少?
1/2*n(3n+1).

∵a(n+1)＝an+3n+2
∴a(n+1)－an＝3n+2
则
an－a(n-1)=3(n-1) + 2
a(n-1)－a(n-2)=3(n-2) + 2
a(n-2)－a(n-3)=3(n-3) + 2
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a3 － a2 =3×2 + 2
a2 － a1 =3×1 + 2
全加,得
an － a1 =3[1+2+3+……+(n-1)] + 2(n-1)
an － 2 =3n(n-1)/2 + 2n -2
an=3n(n-1)/2 + 2n = n(3n+1)/2