(3x+1)²(3x-1)² x(x-5)²-x(x-5)(x+5)
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解决时间 2021-01-25 10:51
- 提问者网友:心牵心
- 2021-01-24 15:23
(3x+1)²(3x-1)² x(x-5)²-x(x-5)(x+5)
最佳答案
- 五星知识达人网友:旧脸谱
- 2021-01-24 16:19
(3x+1)²(3x-1)²
=(9x²-1)²
=81x的4次幂 - 18x² +1
.
x(x-5)²-x(x-5)(x+5)
=x(x-5)(x-5-x-5)
=-10x(x-5)
=(9x²-1)²
=81x的4次幂 - 18x² +1
.
x(x-5)²-x(x-5)(x+5)
=x(x-5)(x-5-x-5)
=-10x(x-5)
全部回答
- 1楼网友:十鸦
- 2021-01-24 17:27
(3x+1)²(3x-1)²
=(3x+1)(3x+1)(3x-1)(3x-1)
=(3x+1)(3x-1)X(3x+1)(3x-1)
=(9x²-1)X(9x²-1)
=(9x²-1)²
=81x^4-18x² +1
x(x-5)²-x(x-5)(x+5)
=x(x-5)(x-5)-x(x-5)(x+5)
=x(x-5)(x-5-x-5)
=-10x(x-5)
=(3x+1)(3x+1)(3x-1)(3x-1)
=(3x+1)(3x-1)X(3x+1)(3x-1)
=(9x²-1)X(9x²-1)
=(9x²-1)²
=81x^4-18x² +1
x(x-5)²-x(x-5)(x+5)
=x(x-5)(x-5)-x(x-5)(x+5)
=x(x-5)(x-5-x-5)
=-10x(x-5)
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