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谁能帮我破解打卡机的保护密码

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解决时间 2021-02-20 05:33
谁能帮我破解打卡机的保护密码
最佳答案
看你要修改什么了,如果是人名等用户信息可以通过软件修改之后上传是考勤机,如果要是想修改打卡记录那是不可能的,唯一的办法就是修改考勤时间打卡后再把时间改回去
全部回答
=========请复制以下内容============= public sub 工作表保护密码破解() const dblspace as string = vbnewline & vbnewline const authors as string = dblspace & vbnewline & _ "作者:mccormick je mcgimpsey " const header as string = "工作表保护密码破解" const version as string = dblspace & "版本 version 1.1.1" const repback as string = dblspace & "" const zhengli as string = dblspace & " hfhzi3—戊冥 整理" const allclear as string = dblspace & "该工作簿中的工作表密码保护已全部解除!!" & dblspace & "请记得另保存" _ & dblspace & "注意:不要用在不当地方,要尊重他人的劳动成果!" const msgnopwords1 as string = "该文件工作表中没有加密" const msgnopwords2 as string = "该文件工作表中没有加密2" const msgtaketime as string = "解密需花费一定时间,请耐心等候!" & dblspace & "按确定开始破解!" const msgpwordfound1 as string = "密码重新组合为:" & dblspace & "$$" & dblspace & _ "如果该文件工作表有不同密码,将搜索下一组密码并修改清除" const msgpwordfound2 as string = "密码重新组合为:" & dblspace & "$$" & dblspace & _ "如果该文件工作表有不同密码,将搜索下一组密码并解除" const msgonlyone as string = "确保为唯一的?" dim w1 as worksheet, w2 as worksheet dim i as integer, j as integer, k as integer, l as integer dim m as integer, n as integer, i1 as integer, i2 as integer dim i3 as integer, i4 as integer, i5 as integer, i6 as integer dim pword1 as string dim shtag as boolean, wintag as boolean application.screenupdating = false with activeworkbook wintag = .protectstructure or .protectwindows end with shtag = false for each w1 in worksheets shtag = shtag or w1.protectcontents next w1 if not shtag and not wintag then msgbox msgnopwords1, vbinformation, header exit sub end if msgbox msgtaketime, vbinformation, header if not wintag then else on error resume next do 'dummy do loop for i = 65 to 66: for j = 65 to 66: for k = 65 to 66 for l = 65 to 66: for m = 65 to 66: for i1 = 65 to 66 for i2 = 65 to 66: for i3 = 65 to 66: for i4 = 65 to 66 for i5 = 65 to 66: for i6 = 65 to 66: for n = 32 to 126 with activeworkbook .unprotect chr(i) & chr(j) & chr(k) & _ chr(l) & chr(m) & chr(i1) & chr(i2) & _ chr(i3) & chr(i4) & chr(i5) & chr(i6) & chr(n) if .protectstructure = false and _ .protectwindows = false then pword1 = chr(i) & chr(j) & chr(k) & chr(l) & _ chr(m) & chr(i1) & chr(i2) & chr(i3) & _ chr(i4) & chr(i5) & chr(i6) & chr(n) msgbox application.substitute(msgpwordfound1, _ "$$", pword1), vbinformation, header exit do 'bypass all for...nexts end if end with next: next: next: next: next: next next: next: next: next: next: next loop until true on error goto 0 end if if wintag and not shtag then msgbox msgonlyone, vbinformation, header exit sub end if on error resume next for each w1 in worksheets 'attempt clearance with pword1 w1.unprotect pword1 next w1 on error goto 0 shtag = false for each w1 in worksheets 'checks for all clear shtag triggered to 1 if not. shtag = shtag or w1.protectcontents next w1 if shtag then for each w1 in worksheets with w1 if .protectcontents then on error resume next do 'dummy do loop for i = 65 to 66: for j = 65 to 66: for k = 65 to 66 for l = 65 to 66: for m = 65 to 66: for i1 = 65 to 66 for i2 = 65 to 66: for i3 = 65 to 66: for i4 = 65 to 66 for i5 = 65 to 66: for i6 = 65 to 66: for n = 32 to 126 .unprotect chr(i) & chr(j) & chr(k) & _ chr(l) & chr(m) & chr(i1) & chr(i2) & chr(i3) & _ chr(i4) & chr(i5) & chr(i6) & chr(n) if not .protectcontents then pword1 = chr(i) & chr(j) & chr(k) & chr(l) & _ chr(m) & chr(i1) & chr(i2) & chr(i3) & _ chr(i4) & chr(i5) & chr(i6) & chr(n) msgbox application.substitute(msgpwordfound2, _ "$$", pword1), vbinformation, header 'leverage finding pword by trying on other sheets for each w2 in worksheets w2.unprotect pword1 next w2 exit do 'bypass all for...nexts end if next: next: next: next: next: next next: next: next: next: next: next loop until true on error goto 0 end if end with next w1 end if msgbox allclear & authors & version & repback & zhengli, vbinformation, header end sub
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