数学好的回答~~!!!
(x-1)(x-3)(x+2)(x+4)+24 因式分解~~!!!
数学好的回答~~!!!
(x-1)(x-3)(x+2)(x+4)+24 因式分解~~!!!
(x-1)(x+2)=(x^2+x-2)
(x-3)(x+4)=(x^2+x-12)
设u=x^2+x
那么(x-1)(x-3)(x+2)(x+4)+24 =(u-2)(u-12)+24=u^2-14u+48=(u-6)(u-8)
u-6=x^2+x-6=(x+3)(x-2)
u-8=x^2+x-8=(x+1/2)^2-33/4=(x+1/2+√33/2)(x+1/2-√33/2)
所以
(x-1)(x-3)(x+2)(x+4)+24 =(x+3)(x-2)(x+1/2+√33/2)(x+1/2-√33/2)
X的4次方加2倍X的立方减13倍X的平方减14X加48