(3x^2/4y)^2*2y/3x+x^2/2y^2÷2y^2/x
答案:2 悬赏:30 手机版
解决时间 2021-01-23 10:06
- 提问者网友：蓝莓格格巫
- 2021-01-22 23:27
(3x^2/4y)^2*2y/3x+x^2/2y^2÷2y^2/x
最佳答案
- 五星知识达人网友：雾月
- 2021-01-23 00:38
解1题： ^ 表示乘方
原式=9x^4/(16y²)×2y/(3x)+x²/(2y²)×x/(2y²)
=3x³/(8y)+x³/(4y^4)
=3x³y³/(8y^4)+2x³/(8y^4)
=(3x³y³+2x³)/(8y^4)
原式=9x^4/(16y²)×2y/(3x)+x²/(2y²)×x/(2y²)
=3x³/(8y)+x³/(4y^4)
=3x³y³/(8y^4)+2x³/(8y^4)
=(3x³y³+2x³)/(8y^4)
全部回答
- 1楼网友：一叶十三刺
- 2021-01-23 00:47
(3x^2/4y)^2*2y/3x+x^2/2y^2÷2y^2/x=9x^4/16y^2*2y/3x+x^2/2y^2*x/2y^2=3x^3/8y+x^3/4y^4=x^3/8y^4(3y^3+2)
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