求 一编程题

每个苹果0.8元，第一天买两个苹果，从第二天开始，每天买前一天的２倍，直到购买的苹果个数达到不超过１００的最在数。编写程序求每天平均花多少钱？

//每个苹果0.8元，第一天买两个苹果，从第二天开始，每天买前一天的２倍，
//直到购买的苹果个数达到不超过１００的最在数。编写程序求每天平均花多少钱？

#include <iostream.h>

int main( void )
{
int day;
int number;
float sum;
int temp;
sum = 0;
day = 0;
number = 2;
while( sum < 100 )
{
day++;
sum += number;
if( sum > 100 )
{
sum = sum -number;
day--;
break;
}
temp = 2 * number;
number = temp;
cout<<sum<<endl;
}
cout<<day<<"一共花费:"<<0.8*sum/day<<endl;
return 1;
}

用vb写的，你看看行不。

Private Sub Command1_Click()

Dim Data As Integer Dim number As Integer Dim money1 As Single Dim money2 As Single Dim times As Integer Dim x As Integer Data = 1 number = 2 money = number * 0.8 money2 = money + money2 Print "**************" & vbCrLf & "第"; Data; "天" Print number; "个苹果" Print "今天花费"; money; "元" Print "累计共花费"; money2; "元" Do Until x >= 100 'DO循环，直到X大于100退出循环 If times = 2 Then Print "**************" & vbCrLf & "第"; Data; "天" Print number; "个苹果" Print "今天花费"; money; "元" Print "累计共花费"; money2; "元" Print "平均每天花费"; money2 / Data; "元" Else End If

Data = Data + 1 ' 增加一天 number = number * 2 ' 数量乘2 money = number * 0.8 '价格 money2 = money + money2 '总花费 x = number times = 2 Loop End Sub

#include int main() { int temp,n; int total; float money; total = 0; n = 0; temp = 2; while ( temp<100 ) { total+=temp; n++; temp*=2; } money = 0.8*(float)total/n; printf("%.2f\n",money); return 0; }