四道分解因式:1.(x+y)²-4(x+y-1) 2.(x²+y²)²-4x²y²
答案:3 悬赏:30 手机版
解决时间 2021-03-21 14:17
- 提问者网友:雪舞兮
- 2021-03-21 09:07
-2x)².(x²-6x²+9(x-y)²+6y²+2(x².(x+y)²-2x)+1 43
最佳答案
- 五星知识达人网友:孤老序
- 2021-03-21 10:25
解: 1.(x+y)²-4(x+y-1) =(x+y)²-4(x+y)+4 =(x+y-2)² 2.(x²+y²)²-4x²y² =(x²+y²+2xy)(x²+y²-2xy) =(x+y)²(x-y)² 3.(x²-2x)²+2(x²-2x)+1 =(x²-2x+1)² =(x-1)⁴ 4.(x+y)²-6x²+6y²+9(x-y)² =(x+y)²-6(x²-y²)+[3(x-y)]² =[(x+y)-3(x-y)]² =(x+y-3x+3y)² =(-2x+4y)² =4(x-2y)²
全部回答
- 1楼网友:狂恋
- 2021-03-21 12:28
您好:
x²-y²+4xy
=(x²+4xy+4y²)-5y²
= (x+2y)²-5y²
=(x+2y+√5y)(x+2y-√5y)
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- 2楼网友:末日狂欢
- 2021-03-21 11:09
+y²+6y²-y² 2; =;-4(x+y-1) =(x+y)²+2xy)(x²-2xy) =(x+y)² =(4y-2x)².(x+y)².(x+y)².(x² =[(x-1)²+9(x-y)².(x+y)²-6(x²-2x)+1 =(x²-2x)² (x-y)² -2x+1)² ]²-6x² 3; =[(x+y)-3(x-y)]² =(x+y)².(x²y²+y²-6(x+y)(x-y)+9(x-y)²)²-4(x+y)+4 =(x+y-2)²+2(x²)+9(x-y)² =(x-1)^4 4;-4x²+y² =(x۵
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