已知x-3y=0,求(x²-2xy+y²/x-y)-2y的值
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解决时间 2021-11-12 20:48
- 提问者网友：浪荡绅士
- 2021-11-12 07:42
已知x-3y=0,求(x²-2xy+y²/x-y)-2y的值
最佳答案
- 五星知识达人网友：枭雄戏美人
- 2021-11-12 09:01
(x²－2xy＋y²)/(x－y)－2y
=[(x－y)²/(x－y)]－2y
=(x－y)－2y
=x－3y
=0
=[(x－y)²/(x－y)]－2y
=(x－y)－2y
=x－3y
=0
全部回答
- 1楼网友：纵马山川剑自提
- 2021-11-12 11:07
(x²-2xy+y²/x-y)-2y
=（x-y）²/（x-y）-2y
=x-y-2y
=x-3y
=0
=（x-y）²/（x-y）-2y
=x-y-2y
=x-3y
=0
- 2楼网友：行路难
- 2021-11-12 10:23
(x²-2xy+y²/x-y)-2y 通分，得
(x²-2xy+y²-2xy+2y²)/(x-y)
=(x²-4xy+3y²)/(x-y)
=(x-y)(x-3y)/(x-y)
=x-3y
由题知 x-3y=0
(x²-2xy+y²-2xy+2y²)/(x-y)
=(x²-4xy+3y²)/(x-y)
=(x-y)(x-3y)/(x-y)
=x-3y
由题知 x-3y=0
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